Answer:
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Step-by-step explanation:
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First, lets gather the information given in the problem :
Mr. G's total students = 57
Mr. G's band students = 25
Clue 1 : Since there are 25 students that take band, that means that there are 57-25 = 32 students who do not take band = 32 students who take choir or math or both.
Mr. G's band / choir / band and choir students = 48
Clue 2 : Since there are 25 students that take band and there are 48 that take either band / choir/ or both, that means we have 48-25 = 23 students who do not take band = 23 students who must take choir but not band. Thus
Mr. G's choir students = 23
So, we have the following :
Mr. G's total students = 57
Mr. G's band students = 25
Mr. G's choir students = 23
However, 25 + 23 = 48. Thus, we have 9 students not accounted for. These must be his math students. Hence,
Mr. G's total students = 57
Mr. G's band students = 25
Mr. G's choir students = 23
Mr. G's math students = 9
Next, they tell us that 9 students take both math and choir.
Without the vin diagrams, this is all I can provide.
Answer:
A ≈ 81.487 in²
Step-by-step explanation:
You know that circumference is C = 2πr, where r is the radius.
So,
C = 2πr
32 = 2(3.14)r
r ≈ 5.093 in
We also know that the formula for the area of a circle is A = πr², so:
A = πr²
A = (3.14)(5.093)²
A ≈ 81.487 in²
The last one. Graphing because they found where the two line’s intersected on the graph