Question

14a^8c^9 + 2a^4c^3 [Algebra]

Answer 1

Answer:

im not the best at algebra but

2a+3b+4c

Step-by-step explanation:

subtract

(2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

add

=(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

then subtract

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c