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3 years ago

15

In isosceles △ABC, points D and F are on leg CB while point E is on leg AB so that AC = AD = DE = EF = BF. Find the measures of

the angles of △ABC.

2 answers:

Aleks [24]3 years ago

5 0

Answer:

good job

Step-by-step explanation:

Solnce55 [7]3 years ago

3 0

Answer:

Abs 12 -- ef de Venta de casas en Venta por que es UN hombre de casas abs

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The ground floor of a building is 18 feet in height and each floor above it is 12 feet in height.

nadezda [96]

18+12*4=18+48=66 ft
1st floor is 18ft
next 4 are 12ft

5 0

3 years ago

A commercial jet has been instructed to climb from its present altitude of 6000 feet to a cruising altitude of 30,000 feet. If t

Lunna [17]

An easier way of doing this would be to subtract the initial attitude from the final attitude and divide by the rate of increase
= 30000 - 6000÷4000
= 24000÷4000
=6mins

8 0

3 years ago

A basketball player made 40% of the shots she attempted.if she made 32 baskets, how many shots did she attend?

malfutka [58]

32 divde by 2 = 16 (50%)
32 divde by 10 = 3.2 (10%)
16 - 3.2 = 12.8 (40%)
3.2 times 4 = 12.4 (40%)

You would round the number to the nearest whole because you can't make a . of a shot. Therefore the answer would be that she made 12 shots.

Hope this helps!

6 0

4 years ago

The minimum/maximum value of the function y = a(x − 2)(x − 1) occurs at x = d, what is the value of d?

daser333 [38]

Answer:

$d=\frac{3}{2}=1.5$

Step-by-step explanation:

We have the function:

$y=a(x-2)(x-1)$

And we want to find x=d for which the minimum/maximum value will occur.

Notice that our function is a quadratic in factored form.

Remember that the minimum/maximum value always occurs at the vertex point.

And remember that the x-coordinate of the vertex is the axis of symmetry.

Since a quadratic is always symmetrical on both sides of its axis of symmetry, a quadratic’s axis of symmetry is the average of the two roots/zeros of the quadratic.

Therefore, the value x=d such that it produces the minimum/maximum value is the average of the two roots.

Our factors are <em>(x-2) </em>and <em>(x-1)</em>.

Therefore, our roots/zeros are <em>x=1, 2</em>.

So, the average of them are:

$d=\frac{1+2}{2}=3/2=1.5$

Therefore, regardless of the value of <em>a</em>, the minimum/maximum value will occur at <em>x=d=1.5</em>.

Alternative Method:

Of course, we can also expand to confirm our answer. So:

$y=a(x^2-2x-x+2)\\y=a(x^2-3x+2)\\y=ax^2-3ax+2a$

The x-coordinate of the vertex is still going to be the place where the minimum/maximum is going to occur.

And the formula for the vertex is:

$x=-\frac{b}{2a}$

So, we will substitute <em>-3a</em> for <em>b</em> and <em>a</em> for <em>a</em>. This yields:

$x=-\frac{-3a}{2a}=\frac{3}{2}=1.5$

Confirming our answer.

4 0

3 years ago

Which of the following points does Not lie on the graph of y =3x

nalin [4]

Answer:

(2,6)

Step-by-step explanation:

<u><em>The options of the questions are</em></u>

(0,1) (1,3) (2,6) (3,27)

and the given function is $y=3^x$

we know that

If a ordered pair lie on the graph of the given equation, then the ordered pair must satisfy the given equation

<u><em>Verify each ordered pair</em></u>

case 1) (0,1)

substitute the value of x and the value of y in the linear equation and then compare the results

$1=3^0$

$1=1$ ----> is true

so

The ordered pair lie on the graph of the given equation

case 2) (1,3)

substitute the value of x and the value of y in the linear equation and then compare the results

$3=3^1$

$3=3$ ----> is true

so

The ordered pair lie on the graph of the given equation

case 3) (2,6)

substitute the value of x and the value of y in the linear equation and then compare the results

$6=3^2$

$6=9$ ----> is not true

so

The ordered pair not lie on the graph of the given equation

case 4) (3,27)

substitute the value of x and the value of y in the linear equation and then compare the results

$27=3^3$

$27=27$ ----> is true

so

The ordered pair lie on the graph of the given equation

8 0

3 years ago