Find the distance between the points given. (0,5) and (-5,0)

Mathematics

1 answer:

galina1969 [7]3 years ago

5 0

Answer:

5 $\sqrt{2}$

Step-by-step explanation:

Calculate the distance between the points using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (0, 5) and (x₂, y₂ ) = (- 5, 0)

d = $\sqrt{(-5-0)^2+(0-5)^2}$

= $\sqrt{(-5)^2+(-5)^2}$

= $\sqrt{25+25}$ = $\sqrt{50}$ = 5 $\sqrt{2}$ ← exact value

You might be interested in

I'm not sure how to answer this,

Sindrei [870]

Answer:

Addition

Step-by-step explanation:

if you just add 32 to both sides you'll get h=3+g

3 0

2 years ago

Find (fog)(x) when f(x)=x^2-7x+12 and g(x)=3/x^2-16

Kazeer [188]

Answer:

$f( \frac{3}{ {x}^{2} - 16 } ) = ({\frac{3}{ {x}^{2} - 16 }})^{2} - 7(\frac{3}{ {x}^{2} - 16 }) + 12 \\ = \frac{9}{ {x}^{4} - 32 {x}^{2} + 256 } - \frac{21}{ {x}^{2} - 16} + 12$

4 0

2 years ago

A. Write an expression to represent the difference between the two points shown on the number line.

Maru [420]

-1.6 - 0.3
I hope this hepled you and that the answer is correct

8 0

3 years ago

Read 2 more answers

I need some help with this calculus 1 question.

Cerrena [4.2K]

Answer:

(a) f'(1)=-4

(b) y+4x-4=0

Step-by-step explanation:

<u>Tangent Line of a Function</u>

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

$y=x-x^5$