Ask question

Ask question

All categories

3 years ago

6

A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at

a certain time of day, how long is the building's shadow at that time? PLEASE HELP

1 answer:

Soloha48 [4]3 years ago

7 0

The equation you can use to solve the problem is;

50/30 = 300/x

Next Cross Multiply

50x = 9000

x = 9000/50

x = 180

The building's shadow is 180 feet tall

You might be interested in

Which expression is equivalent to (xy)z?<br><br>A (x+y)+z<br>B 2z(xy)<br>C x(yz)<br>D x(y+z)

qwelly [4]

Answer:

c

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

THIS IS VERY IMPORTANT!

tatyana61 [14]

Answer:

I think Leslie Is 20

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Solve <br><br> 9x-14-2x=5(2x-6)

deff fn [24]

$9x-14-2x=5(2x-6)\qquad\text{use distributive property}\\\\(9x-2x)-14=(5)(2x)+(5)(-6)\\\\7x-14=10x-30\qquad\text{add 14 to both sides}\\\\7x=10x-16\qquad\text{subtract 10x from both sides}\\\\-3x=-16\qquad\text{divide both sides by (-3)}\\\\\boxed{x=\dfrac{16}{3}}$

8 0

3 years ago

1854times845 could someone help me

vivado [14]

Answer:

1,566,630

Step-by-step explanation:

1854*845=1,566,630

8 0

3 years ago

According to a study conducted in one city, 35% of adults in the city have credit card debts more than $2.000. A simple random s

BabaBlast [244]

Answer:

Binomial; \mu p=87.5, \sigma p=7.542

Step-by-step explanation:

a distribution is said be a binomial distribution iff

The probability of success of that event( let it be p) is same for every trial
each trial should have 2 outcome : p or (1-p) i.e, success or failure only.
there are fixed number of trials (n)
the trials are independent

here, the trials are obviously independent ( because, one person's debt doesn't influence the other person's)

here n=250

the probability of success(0.35) is same for every trial

(35/100=0.35 is the required p here)

$\mu_{p} =n*p=250*\frac{35}{100} =250*0.35=87.5$

[since, the formula for $\mu _{p} =n*p$ ]

$\sigma _{p} =\sqrt{n*(p)*(1-p)} = \sqrt{250*0.35*(1-0.35)} = 7.542 ( approximately)$

[since, the formula for [tex]\sigma _{p} =\sqrt{n*(p)*(1-p)}

therefore, it is Binomial; \mu p=87.5, \sigma p=7.542

4 0

3 years ago