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Setler [38]
3 years ago
6

How to write 111101 to base 2

Mathematics
1 answer:
Hoochie [10]3 years ago
7 0

Answer:

11011000111111101

Step-by-step explanation:

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horsena [70]

Answer:

x=2/5

Step-by-step explanation:

4 0
2 years ago
Which of the following graphs represents the solution set for 7(4x – 1 ) + 6x > –279? PLEASE HELP
Luda [366]
First, solve the inequality:
7(4x - 1 ) + 6x \ \textgreater \  -279\\
28x-7+6x\ \textgreater \ -279\\
34x\ \textgreater \ -272\\
x\ \textgreater \ -8
Since x is <u>greater than</u> -8, you have the arrow point up the graph towards the positive side starting at -8.
Since it's greater than but not equal to -8, the circle is open.

Thus your graph is D.
3 0
2 years ago
Joe concluded that the expression 3x + 15 + 2x is equivalent to the expression 5(x + 3). Which of these best explains how Joe re
marta [7]

Answer:

c

Step-by-step explanation:

4 0
3 years ago
The function f is defined by f(x) = 2x²-1.<br> Find f (2x).
umka21 [38]

Answer: f(2x)=8x^2-1

Step-by-step explanation:

All that is required here is to substitute x = 2x into the right side in the same way that is done for a numeric value.

f(2x) = 2(2x)^2-1\\f(2x) = 2(4)x^2-1\\f(2x) = 8x^2-1\\

5 0
3 years ago
What multiplies to 16 and adds to negative 12
Romashka-Z-Leto [24]
Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm


we will solve with math
xy=16
x+y=-12
minus  x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}


0=x^2+12x+16
a=1
b=12
c=16

x=\frac{-12+/- \sqrt{12^{2}-4(1)(16) }}{2(1)}
x=\frac{-12+/- \sqrt{144-64 }}{2}
x=\frac{-12+/- \sqrt{80}}{2}
x=\frac{-12+/- 4\sqrt{5}}{2}
x=\frac{-6+/- 2\sqrt{5}
x=\frac{-6+ 2\sqrt{5} or \frac{-6- 2\sqrt{5}

aprox
x=-1.52786 or -10.4721

those are the numbers

the numbes are -1.52786 or -10.4721

6 0
3 years ago
Read 2 more answers
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