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Dmitry [639]
2 years ago
9

Look at Michael expression. Why do you add 6+4 first​

Mathematics
1 answer:
natali 33 [55]2 years ago
3 0

Answer:

probably cuz its in parentheses but there's no picture

Step-by-step explanation:

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a,b) you can place all 17 in the middle and both circle will have 17 each. then remove 2 and place one each on separate sides. you can do this 8 times so that at the you'll end up with 1 in the middle and 8 each on separate sides.

the ways to do is then 9.

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1 3/5 •1 2/5= Find the value of each expression in lowest terms. That dot between the numbers is times
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3 years ago
What kind of salad do snowmen eat? Punchline 73 answer key
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Step-by-step explanation:

6 0
3 years ago
Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.
SOVA2 [1]

Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at (0,1).

The graph has an x-intercept at (-7,0).

Step-by-step explanation:

Given: The graph is y=\sqrt[3]{x-1}+2

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of (-\infty, \infty).

To find the y-intercept:  To find the y-intercept, substitute x=0 in y=\sqrt[3]{x-1}+2.

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}

Thus, the y-intercept is (0,1)

To find the x-intercept: To find the x-intercept, substitute y=0 in y=\sqrt[3]{x-1}+2 .

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}

Thus, the x-intercept is (-7,0)

8 0
2 years ago
Read 2 more answers
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