Step-by-step explanation:
5r+1=a(m+r)
or , 5r+1=am+ar
or, 5r-ar=am-1
or , r(5-a)=1(am-1)
: <u>r</u><u> </u> =<u>(</u><u>am-1)</u>
1 (5-a)
For a horizontal line, gradient is zero;
y=mx+c
since m=0
y=c
Replacing for y from given point;
-1=c
c=-1
y-1
Well, hopefully you know how to get Kelvin. For example. 1 degrees Celsius to Kelvin is 274.15. Celsius - Kelvin 273.15. Anyway, two other related equations would be x Celsius + 273.15 = y (Kelvin) and Celsius - Kelvin = Add 273.15
If the temperature in Celsius is 23 degrees, it would be 296.15 Kelvin.
300 Kelvin is greater than 25 Celsius. I got my answer because I know to get Celsius, you would add 273.15 to the celsius. 25 + 273.15 = 298.15. So 300 Kelvin is greater than 25 Degrees Celsius.
I hope this helps!!
8.2 the decimal is 8.124 but you just round
