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3 years ago

What is the slope of the line that passes through the points (−8,−1) and (−6,−2)? Write your answer in simplest form.

Mathematics

1 answer:

4vir4ik [10]3 years ago

6 0

Answer:

m = -1/2

Step-by-step explanation:

Recall that slope = (change in y) / (change in x).

Going from (−8,−1) to (−6,−2), x increases by 2 (because -6 - (-8) = 2), and

y decreases by 1. Thus, the slope here is

m = (change in y) / (change in x) = (-1) / 2 = -1 / 2

m = -1/2

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3 years ago

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Write the equation of the parabola y=x^2 + 8x - 51

nikdorinn [45]

You already have the equation! If you want it in vertex form, do this:

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3 years ago

e. Translate the word problem below into an equation; then solve. It only takes Vera 2 hours to sew 1 dress, but it takes Ivy 4

Daniel [21]

Using the together rate, it is found that it would take them 16 hours to sew 12 dresses.

<h3>What is the together rate?</h3>

The together rate is the <u>sum of each separate rate</u>.

In this problem, we have that:

Vera's rate is of 1/2.

Ivy's rate is of 1/4.

Hence, the together rate is the time it would take them to produce one dress working together, and is given by:

$\frac{1}{x} = \frac{1}{2} + \frac{1}{4}$

$\frac{1}{x} = \frac{2 + 1}{4}$

$3x = 4$

$x = \frac{4}{3}$

Then one dress takes $\frac{4}{3}$ of an hour, and the time for twelve dresses is:

$t = 12 \times \frac{4}{3} = 4(4) = 16$

It would take them 16 hours to sew 12 dresses.

To learn more about the together rate, you can take a look at brainly.com/question/25159431

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2 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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3 years ago

Help!!! Please please I don’t know this at all

Lesechka [4]

Answer:

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Step-by-step explanation:

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3 years ago