Explanation:
The given data is as follows.
Partition coefficient, K = 6.2
Volume of phase 1, 
= 74.0 mL
Volume of phase 2, 
= 17.0 mL
So, after one extraction fraction of solute remaining is given as follows.
q = 
After 3 times extraction, fraction of S remaining is as follows.
q = ![[\frac{V_{1}}{V_{1} + KV_{2}}]^{3}](https://tex.z-dn.net/?f=%5B%5Cfrac%7BV_%7B1%7D%7D%7BV_%7B1%7D%20%2B%20KV_%7B2%7D%7D%5D%5E%7B3%7D)
Putting the given values into the above formula as follows.
q =
= ![[\frac{74.0 ml}{74.0 ml + 6.2 \times 17.0 ml}]^{3}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B74.0%20ml%7D%7B74.0%20ml%20%2B%206.2%20%5Ctimes%2017.0%20ml%7D%5D%5E%7B3%7D)
= ![[\frac{74.0 ml}{179.4 ml}]^{3}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B74.0%20ml%7D%7B179.4%20ml%7D%5D%5E%7B3%7D)
= 0.0699
Thus, we can conclude that the fraction of S remaining in the aqueous phase is 0.0699.
The answer to 1 is D the answer to 2 is B the answer for 3 is C the answer to 4 is A and the answer to 5 is c or b
Answer:
of unshared pairs
of unshared electrons
of unlone pairs
of shared electrons
Explanation:
only this word sAna Tama HAHAHA
Any type of electromagnetic energy's wavelengths that are shorter than a type of electromagnetic energy's wavelengths is to the left of that type of electromagnetic energy on the diagram. Hence, the wavelength of a type of energy decreases as you progress to the left on the diagram and left of the green light (in the visible spectrum).
yes because they are inert or inactive at normal temperature, they are inactive because their outer most orbit contain either 2 or 8 electrons.that make them stable
