1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
velikii [3]
4 years ago
8

The Boy In The Striped Pajama

Chemistry
1 answer:
spin [16.1K]4 years ago
7 0

I don't know but at the end he dies

You might be interested in
The gas in the piston is being heated, and the piston has moved upward. The observation will be summarized in a row of the incom
Nina [5.8K]
The student would fill out the second row, stating that the volume increases as the temperature increases.

This phenomenon is in accordance with Charles's law, which states that for a fixed amount of gas at a constant pressure, the volume of the gas is directly proportional to the absolute temperature of the gas. All three of the gas laws are combined to form the ideal gas law.
5 0
3 years ago
What is the freezing point of a solution prepared from 45.0 g ethylene glycol (C2H6O2) and 85.0 g H2O? Kf of water is 1.86°C/m.
Andrews [41]

Answer:

T_{sol}=-15.9\°C

Explanation:

Hello,

In this case, we can analyze the colligative property of solutions - freezing point depression - for the formed solution when ethylene glycol mixes with water. Thus, since water freezes at 0 °C, we can compute the freezing point of the solution as shown below:

T_{sol}=T_{water}-i*m*Kf

Whereas the van't Hoff factor for this solute is 1 as it is nonionizing and the molality is:

m=\frac{mol_{solute}}{kg\ of\ water}=\frac{45.0g*\frac{1mol}{62g} }{85.0g*\frac{1kg}{1000g} } =8.54m

Thus, we obtain:

T_{sol}=0\°C+(-8.54m*1.86\frac{\°C}{m} )\\\\T_{sol}=-15.9\°C

Best regards.

6 0
3 years ago
An athlete has 13
FrozenT [24]
Answer = 23.2146762081 pounds.
-------------------------------------------------

13% of 81 = 10.53
10.53 converted to pounds (lbs) = 23.21......pounds
6 0
3 years ago
A hot piece of copper was dropped into 155 g of water at 23.6 °C and 2,100 J of energy was transferred to the water. What is the
BlackZzzverrR [31]

Answer:

26.8 °C

Explanation:

Step 1: Given and required data

  • Mass of water (m): 155 g
  • Energy transferred to the water (Q): 2100 J
  • Initial temperature of the water (T₂): 23.6 °C
  • Final temperature of the water (T₁): ?
  • Specific heat of water (c): 4.184 J/g.°C

Step 2: Calculate the final temperature of the water

We will use the following expression.

Q = c × m × (T₂ - T₁)

T₂ = 2100 J/(4.184 J/g.°C) × 155 g + 23.6 °C = 26.8 °C

5 0
3 years ago
Are the components of a solution fixed?
liq [111]

Answer:

yes

Explanation:

the components of solutions fixed

3 0
3 years ago
Other questions:
  • Base your answer on the information below and your knowledge of chemistry. Methanol can be manufactured by a reaction that is re
    6·1 answer
  • The number of neutrons in the nucleus of an atom can be determined by
    12·1 answer
  • Why was there no increase in the reaction rate with 8 g of substrate as compared to 4 g of substrate?
    14·1 answer
  • (5.93 x 103) (2.3 x10-2)
    13·2 answers
  • How many valence electrons does a neutral atom of silicon have??
    9·1 answer
  • The action of warm air rising and cold air sinking plays a key role in the formation of severe thunderstorms. If the warm surfac
    15·2 answers
  • Which of these equations correctly expresses the self-ionization of water?
    13·1 answer
  • This beaker contains an aqueous solution of copper II nitrate.
    15·1 answer
  • Compare the values of the spin quantum number for two electrons in the same orbital
    9·1 answer
  • How are communication signals on the ground sent to spacecraft?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!