we know that
meter is equal to
centimeters
Step ![1](https://tex.z-dn.net/?f=%201%20)
<u>convert all measurements to centimeters</u>
<u>case 1) </u>![0.81\ m](https://tex.z-dn.net/?f=%200.81%5C%20m)
![0.81\ m = 0.81*100= 81\ cm](https://tex.z-dn.net/?f=%200.81%5C%20m%20%3D%200.81%2A100%3D%2081%5C%20cm%20)
<u>case 2) </u>![1.08\ m](https://tex.z-dn.net/?f=%201.08%5C%20m)
![1.08\ m = 1.08*100= 108\ cm](https://tex.z-dn.net/?f=%201.08%5C%20m%20%3D%201.08%2A100%3D%20108%5C%20cm%20)
<u>case 3) </u>![0.8\ m](https://tex.z-dn.net/?f=%200.8%5C%20m)
![0.8\ m = 0.8*100= 80\ cm](https://tex.z-dn.net/?f=%200.8%5C%20m%20%3D%200.8%2A100%3D%2080%5C%20cm%20)
<u>case 4) </u>![180\ cm](https://tex.z-dn.net/?f=%20180%5C%20cm)
<u>case 5) </u>![18\ cm](https://tex.z-dn.net/?f=%2018%5C%20cm)
Step ![2](https://tex.z-dn.net/?f=%202%20)
<u>Compare the values</u>
we have
![[81,108,80,180,18]](https://tex.z-dn.net/?f=%20%5B81%2C108%2C80%2C180%2C18%5D%20)
the shortest length is ![18](https://tex.z-dn.net/?f=%2018%20)
the longest length is ![180](https://tex.z-dn.net/?f=%20180%20)
Step ![3](https://tex.z-dn.net/?f=%203%20)
<u>Subtract the shortest length from the longest</u>
![180\ cm-18\ cm=162\ cm](https://tex.z-dn.net/?f=%20180%5C%20cm-18%5C%20cm%3D162%5C%20cm%20)
therefore
<u>the answer is</u>
![162\ cm](https://tex.z-dn.net/?f=%20162%5C%20cm)
Answer:
The width of the bathroom is 10ft.
Step-by-step explanation:
To find the area of a rectangle, we use the formula
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>area</em><em> </em><em>=</em><em> </em><em>width x length</em>
So we know that length is equal to 7 ft, and we also know the total area which is 70 sq.ft.
70 = ? x 7
multiplication and division are inverse operations, so we will divide instead
70 divided by 7 = 10
And we are done!!
hope this helps you, feel free to leave any questions in the comments!! :)
Yes you can because you know there still might be more
Answer:
4a + 3d + 15
Step-by-step explanation:
Remove parentheses.
3d + 9 + 4a + 6
Add 9 and 6.
3d + 4a + 15
Reorder 3d and 4a.
4a + 3d + 15