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vladimir1956 [14]
3 years ago
5

Find the value of x that will make A||B

Mathematics
1 answer:
Arturiano [62]3 years ago
3 0

Answer:

x=20

Step-by-step explanation:

Both Angles have the same value, as they are opposite angels.

Set your formula up as

5x+20=3x+60

5x=3x+60-20

2x=40

x=40/2

x=20

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posledela

Answer:

<em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u>2</u></em>

Step-by-step explanation:

<u>f</u><u>{</u><u>5</u><u>}</u> = <u>6</u><u>(</u><u>5</u><u>^</u><u>2</u><u>)</u><u> </u><u>+</u><u> </u><u>2</u><u>(</u><u>5</u><u>)</u><u> </u><u>-</u><u> </u><u>7</u>

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3 years ago
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Answer:

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Step-by-step explanation:

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The altitudes at X, Y, and Z are perpendicular to sides EF, EG, and FG, and pass through the incenter, so X, Y, Z are points on the incircle.

A is the center of circles through E, F, and G, and through X, Y, and Z.

6 0
3 years ago
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In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.
Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

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Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

BC^{2} = DB^{2} +CD^{2}

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Since given AD=BC,let us plugin BC=x in above step.

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Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}

AC^{2} =\frac{193}{36}

AC=\sqrt{\frac{193}{36} } = 2.315cm

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Answer:

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Step-by-step explanation:

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