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Alex Ar [27]
3 years ago
9

What is the name of the relationship between 1 and 4? Parallel Lines and Transversals A. corresponding angles B. alternate inter

ior angles C. obtuse angles D. adjacent angles
Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0
<span>The correct answer is B. alternate interior angles. Both angles are on the inside of the two parallel lines, making them interior angles, and they are alternate because they're not on the same sides of the transversal line (the line that cuts through the parallel lines). A is incorrect because corresponding angles are those that are in the same position on both parallel lines, C is incorrect because it's impossible to tell with the information given if the angles are obtuse, and D is incorrect because adjacent angles are those that are next to each other.</span>
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Citrus2011 [14]

Answer:

Step-by-step explanation:

b

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1 year ago
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What is the solution to the system of equations?<br><br> -4y – 3x = -11<br><br> x – 2y = 17
LekaFEV [45]

Answer:

Step-by-step explanation:

4 0
3 years ago
I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a
solong [7]

Answer:

\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}

Step-by-step explanation:

40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4

7 0
4 years ago
Multipy the expreshions (2h+2.7) (2h-27)​
Musya8 [376]

Answer:

4h^2-48.6h-72.9

Step-by-step explanation:

(2h+2.7) (2h-27)\\4h^2-54h+5.4h-72.9\\4h^2-48.6h-72.9

5 0
3 years ago
Factor out completly: 6x^2y − 3xy − 24xy^2 + 12y^2
Crank
<h3>I'll teach you how to factor 6x^2y − 3xy − 24xy^2 + 12y^2</h3>

---------------------------------------------------------------------

6x^2y − 3xy − 24xy^2 + 12y^2

Apply exponent rule:

6x^2y-3xy-24xyy+12yy

Rewrite 12 as 4*3

Rewrite -24 as 8*3

Rewrite 6 as 2*3

2*3x^2y-3xy+8*3xyy+4*3yy

Factor out common term 3y:

3y(2x^2-x-8xy+4y)

Factor 2x^2-x-8xy+4y:

3y(2x-1)(x-4y)

Your Answer Is 3y(2x-1)(x-4y)

plz mark me as brainliest if this helped :)

8 0
3 years ago
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