Answer:
0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.
Step-by-step explanation:
The kittens are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x sucesses is given by the following formula:

In which:
x is the number of sucesses.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.

A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.
This means that 
We want 3 boys, so 
The director is going to choose 8 of these kittens at random to be in the commercial.
This means that 
What is the probability that the director chooses 3 boy kittens and 5 girl kittens?
This is P(X = 3).


0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.
The quotient is -8. This being because when a negative number is in parentheses, the negative will be the opposite: Positive. And we know 48 divided by 6 is 8. So the answer is B.
Find the smallest number that is divisible by 2, 3, 4, 5, 6 and add 1.
We need the least common multiple of 2, 3, 4, 5, 6.
2 = 2
3 = 3
4 = 2^2
5 = 5
6 = 2 * 3
LCM = product of common and not common prime factors with larger exponent.
LCM = 2^2 * 3 * 5 = 4 * 3 * 5 = 60
To always have a remainder of 1, you need of add 1 to 60.
The number is 61.
Check:
61/2 = 30 remainder 1
61/3 = 20 remainder 1
61/4 = 15 remainder 1
61/5 = 12 remainder 1
61/6 = 10 remainder 1