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jenyasd209 [6]
2 years ago
9

I don’t know the equation :(

Mathematics
2 answers:
Serhud [2]2 years ago
7 0

Answer:

me too

Step-by-step explanation:

olya-2409 [2.1K]2 years ago
3 0

Answer:  \frac{x^2}{1600} - \frac{y^2}{900} = 1

========================================================

Explanation:

The two focal points are <u>always</u> found on the major axis of the hyperbola. The minor axis runs perpendicular to the major axis.

The two focal points are (-50,0) and (50,0). The midpoint of these focal points is (0,0) and this represents the center of the hyperbola. So (h,k) = (0,0)

These focal points lie along the x axis, meaning each curve opens in a horizontal direction. The "parabola" sub pieces open left/right or east/west. Based on this configuration, we'll use this template

\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1

The more general template is

\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1

but we can ignore the h,k because they're both 0.

-----------------------

So the key is to find the values of 'a' and b.

We're told that the difference in distances is 80 miles. The second hint says that 2a represents this difference. So 2a = 80 leads to a = 40.

To find b, we apply the pythagorean theorem. The 'c' value represents the distance from the center to either focus. In this case, it would be c = 50.

a^2+b^2 = c^2\\\\b^2 = c^2-a^2\\\\b = \sqrt{c^2-a^2}\\\\b = \sqrt{50^2-40^2}\\\\b = \sqrt{2500-1600}\\\\b = \sqrt{900}\\\\b = 30\\\\

We can therefore update the template we were working with earlier

\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\\\\\frac{x^2}{40^2} - \frac{y^2}{30^2} = 1\\\\\frac{x^2}{1600} - \frac{y^2}{900} = 1\\\\\left(\frac{x}{40}\right)^2 - \left(\frac{y}{30}\right)^2 = 1\\\\

The graph is shown below.

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20 x .4 = 8

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Answer:

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i hope I helped in time and you get a great score on your quiz !

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2 years ago
A survey by the Pew Research Center asked a random sample of 2142 U.S. adults and a random sample of 1055 college presidents how
gayaneshka [121]

Answer: 0.0125

Step-by-step explanation:

Given :  A survey by the Pew Research Center asked a random sample of 2142 U.S. adults and a random sample of 1055 college presidents how they would "rate the job the higher education system is doing in providing value for the money.

5% the U.S. adults and 17% of the college presidents provided a rating of "Excellent."

i.e. n_1=2142,\ n_2=1055

p_1=0.05 , p_2=0.17

The standard error of the difference in sample proportions  :-

\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}

=\sqrt{\dfrac{0.05(1-0.05)}{2142}+\dfrac{0.17(1-0.17)}{1055}}\\\\=0.0124867775151\approx0.0125

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5 0
3 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
12345 [234]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

6 0
3 years ago
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