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Rzqust [24]
2 years ago
5

What is the the answer​

Mathematics
1 answer:
timofeeve [1]2 years ago
7 0

Answer: x=r^2 + 10 r + 25

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12<br>121 °<br>9<br>can it make a triangle if so what the area ?<br>​
charle [14.2K]

Answer:

no it can not

Step-by-step explanation:

Triangle is always 180° in total.

7 0
3 years ago
Read 2 more answers
4 ^ (- x) + 5 = 3 ^ x + 4<br><br> A ≈ 3/8<br> B ≈ 7/16<br> C ≈ 1/4<br> D ≈ 5/16
Dafna1 [17]

Answer:

4 ^ (-x) + 5 = 3^ x + 4

Step-by-step explanation

i think its c = 1/4

Pls give brainiest

7 0
2 years ago
Fill out the chart please!
jarptica [38.1K]

1. Mean of the data: 8

2. Median: 8

3. IQR = 4

4. Members that use the facility 10 days a month is: 2.

See reasons below.

<h3>What is the Mean, Median, and Interquartile Range of a Data?</h3>

Mean = sum of all values ÷ number of data values (easily solved using a dot plot

Median = middle value (easily found using a box plot).

Interquartile range (IQR) = Q3 - Q1 (easily found using a box plot).

1. Mean of the data: use the dot plot.

Reasoning: (3 + 3 + 5 + 6 + 6 + 7 + 8 + 8 + 8 + 9 + 10 + 10 + 11 + 12 + 14)/15 = 8

2. Median of the data set: Using the box plot, it is the value indicated by the vertical line that divides the box.

Median = 8

3. IQR = Q3 - Q1 = 10 - 6

IQR = 4

4. Members that use the facility 10 days a month, using the dot plot is: 2. 10 has 2 dots.

Learn more about the mean, median, and interquartile range on:

brainly.com/question/9821103

#SPJ1

4 0
2 years ago
True or False!!!! The measure of a tangent-tangent angle is twice the difference of the measures of the intercepted arcs.
lozanna [386]

answer : False

The measure of a tangent-tangent angle is one - half the difference of the measures of the intercepted arcs.

The diagram is attached below

AB  and BC are the two tangents

By exterior angle theorem

 ∠3 = ∠2 + ∠4

So   ∠2 = ∠3 - ∠4

Now we find angle 3  and 4, we know when a chord and tangent intersect at a point then the measure of angle is one half of measure of intercepted arc

∠3 = \frac{1}{2} * arc(ADC)

∠4 = \frac{1}{2} * arc(AC)

 ∠2 = ∠3 - ∠4

 ∠2 = \frac{1}{2} * arc(ADC)  -  \frac{1}{2} * arc(AC)

∠2 = \frac{1}{2} ( arc(ADC) - arc(AC))

The measure of a tangent-tangent angle is one half the difference of the measures of the intercepted arcs.



7 0
3 years ago
Please help due soon.<br><br> (No Links Allowed)
maxonik [38]

Answer: x = 5, x = -5  If you need more....

x = 5^{1}

x = \sqrt{25}

4 0
3 years ago
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