Question

. Only 2% of a large population of 100-ohm gold-band resistors have resistances that exceed 105 ohms. a. For samples of size 100 from this population, describe the sampling distribution of the sample proportion of resistors that have resistances in excess of 105 ohms. b. What is the probabilit

Answer 1

Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.

• Sampling distribution of proportion, P = 2% = 0.02

• Sample size, n = 100

The sampling distribution of the sample proportion can be calculated thus:

• Distribution of sample proportion = np

Distribution of sample proportion = (100 × 0.02) = 2

Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.

Learn more : brainly.com/question/18405415