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omeli [17]
3 years ago
8

Approximate the value of the square root 100 to the nearest hundredth

Mathematics
1 answer:
nataly862011 [7]3 years ago
3 0
The square root of 100 is exactly 10!
10*10=100
10 squared = 100
Square root of 100=10
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18000 decrease by 15% every year for 3 years
kati45 [8]
1st year= 18000 x 0.85 = 15300
2nd year= 15300 x 0.85 = 13005
3rd year= 13005 x 0.85= 11054.25
8 0
3 years ago
The surface area of 3ft, 7ft, 2ft
Xelga [282]

Answer: 82 ft squared

Step-by-step explanation: The surface area is 2( wl + hl + hw)

so the width is 2 the length is 7 and the height is 3

so it's 2( 14 + 21 + 6) = 2(41) = 82

6 0
3 years ago
At 82°F, a certain insect chirps at a rate of 61 times per minute, and at 91°F, they chirp 124 times per minute. Write an equati
Ganezh [65]

Answer:

y=7x-513

Step-by-step explanation:

Let

x----> the temperature in degrees Fahrenheit

y ---->insect chirping rate in times per minute

we have the ordered pairs

(82,61) and (91,124)

step 1

Find the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{124-61}{91-82}

m=\frac{63}{9}=7

step 2

Find the equation of the line

we know that

The equation in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-intercept

we have

m=7  ---> the units are chirps per minute/degree F

take the point (82,61)

substitute and solve for b

61=7(82)+b

61=574+b

b=-513

substitute

y=7x-513

4 0
3 years ago
A weather service records 28.8 inches of rain over a 12 month period. What is the average rainfall per month for the year?
Basile [38]

Answer:

B) 2.4 inches

Step-by-step explanation:

The total amount of rain is 28.8 inches over 12 months. To find how much rain falls averagely in <em>one </em>month you need to divide the total by the amount of months. 28.8/12 = 2.4

6 0
2 years ago
Circle O and triangle OQR are shown below. What is the length of OQ?
zysi [14]

Answer:

Step-by-step explanation:

A circle is inscribed in an equilateral triangle PQR with centre O. If angle OQR = 30°, what is the perimeter of the triangle?

This is a circle inscribed in an equilateral triangle with side s.

If you are asking for the perimeter of PQR, it is 3s.

If you are asking for the perimeter of OQR, it is (3+23–√3)s

Since OR and SR are the hypotenuses of right triangles with adjacent side equal to ½ s, their length is ½s / cos 30° = (√3) /3.

(3/3)s + ((√3) /3)s + ((√3) /3)s = ((3 + 2√3)/3)s ≈ 2.1547s

Hope it helps

help me by marking as brainliest....

3 0
2 years ago
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