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omeli [17]
4 years ago
8

Approximate the value of the square root 100 to the nearest hundredth

Mathematics
1 answer:
nataly862011 [7]4 years ago
3 0
The square root of 100 is exactly 10!
10*10=100
10 squared = 100
Square root of 100=10
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How can you apply the distributive property to factor out the greatest common factor for 40j - 16 = ?
Ronch [10]
The greatest common factor is 8. So your answer would be: 8(5j - 2) because 8 x 5j= 40j and 8 x 2= 16 
6 0
3 years ago
Carroll’s is putting a border around the edge of a rectangular bulletin board. One side of the bulletin board measures 2 feet an
guapka [62]
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

First let's establish that the problem requires the border to be as long as the total perimeter of the rectangular bulletin board.

Therefore:

Total length of border = Perimeter of rectangular bulletin board

As a rectangle has a total of four sides with two equivalent longer sides and two equivalent shorter sides, we must multiply the value of each of the two sides by two.

Total length of border = 2 ( 2 ) + 2 ( 4 )

Total length of border = 4 + 8

Total length of border = 12 feet

12 > 10

ANSWER:

Therefore, 10 feet of border isn't enough.

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4 0
4 years ago
Subtract 2x^2-3xy+4y^2 from 3x^2-5xy-6y^2
Diano4ka-milaya [45]

Answer:

-x^{2} +2xy+10y^{2}

Step-by-step explanation:

2x^2-3xy+4y^2-(3x^2-5xy-6y^2)\\2x^2-3xy+4y^2-3x^2+5xy+6y^2\\-x^{2} +2xy+10y^{2}

8 0
3 years ago
Simplify the expression 7.8n²+0.5+9n-.0.4-7n+n²​
Natali [406]

The final answer for this question would be.....

8.8n^2+16n+0.1

Hope this helps!!!!

4 0
3 years ago
Read 2 more answers
Sequences:
joja [24]

Answer:

<u>The sequence is</u>

  • 1, 1 + 2, 1 + 2 + 3, 1  + 2 + 3 + 4, ...

Each term is the sum of the consecutive numbers from 1 to that number.

<u>The nth term is the sum of the first n numbers:</u>

  • aₙ = 1 + 2 + 3 + ... + n
  • aₙ = 1/2n(1 + n) (formula for sum of the n terms of arithmetic progression with the first term of 1 and common difference of 1)
  • aₙ = n(n + 1)/2

1) The number of circles in the nth pile is n(n + 1)/2

2) When n tends to infinity the number of circles tends to infinity

4 0
3 years ago
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