At 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the state's eighth graders on this exam is more than 280.
<h3>How to state hypothesis conclusion?</h3>
We are given;
Sample size; n = 78
population standard deviation σ = 37
Sample Mean; x' = 280
Population mean; μ = 287
The school administrator declares that mean score is more (bigger than) 280. Thus, the hypotheses is stated as;
Null hypothesis; H₀: μ > 280
Alternative hypothesis; Hₐ: μ < 280
This is a one tail test with significance level of α = 0.13
From online tables, the critical value at α = 0.13 is z(c) = -1.13
b) Formula for the test statistic is;
z = (x- μ)/(σ/√n)
z = ((280 - 287) *√78 )/37
z = -1.67
c) From online p-value from z-score calculator, we have;
P[ z > 280 ] = 0.048
d) The value for z = -1.67 is smaller than the critical value mentioned in problem statement z(c) = - 1.13 , the z(s) is in the rejection zone. Therefore we reject H₀
e) We conclude that at 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the state's eighth graders on this exam is more than 280.
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Answer:
x=1.2
Step-by-step explanation:
2(5x-4)=4
distribute 2 to 5x and -4
10x-8=4
add 8 to negative 8 and 4
10x=12
now divide both sides by 10
10x/10= 12/10
x=1.2
Step-by-step explanation:
x² + 4x − 4 = 8
x² + 4x − 12 = 0
(x + 6) (x − 2) = 0
x = -6 or x = 2
Answer:
The answer is "19.89".
Step-by-step explanation:
Given:
Solution:
that's why the answer is correct.
Answer:
i think it was -(1/3)
Step-by-step explanation:
