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3 years ago

Solve 9y^2=4. Please Help!

2 answers:

8 0

Hello there!
In this situation you would divide both sides by 9 giving you: y² = 0.444~
Take the square root of both sides and the equation becomes y = √0.444

No problem (thank me later) :-)

34kurt3 years ago

7 0

If you'd rather a fraction answer, then dividing both sides gives you y^2= 4/9. Taking the square root of both sides due to y being squared gives you y= +_ 2/3 ( with the minus under the plus to indicate plus OR minus)

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Novosadov [1.4K]

Answer:

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1. -9

2. -28

3. 54

4. -100

5. -60

6. -0

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8. -135

9. -96

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7 0

2 years ago

4sinθ – 1 = - 3 for 0<θ< 360

EastWind [94]

Answer:

$\theta = 210^\circ$ or $\theta = 330^\circ$

Step-by-step explanation:

$4 \sin \theta - 1 = -3$

$4 \sin \theta = -2$

$\sin \theta = \dfrac{-2}{4}$

$\sin \theta = -0.5$

For sin θ = 0.5, the reference angle is θ = 30 deg.

$\sin 30^\circ = 0.5$

$\theta = 210^\circ$ or $\theta = 330^\circ$

7 0

3 years ago

This is the graph of y = sin(x). Does anyone know the second part?

Alborosie

Answer:

The resulting graph is $y = 5\cdot \sin x$ .

Step-by-step explanation:

The resulting function is of the form:

$y = A\cdot \sin x + k$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$A$ - Amplitude, dimensionless.

$k$ - Midpoint value, dimensionless.

The sine function is bounded, between -1 and 1, and must be multiplied by a stretch factor. That is: $A > 0$ . According to the graph, the function is bounded between 5 ( $y_{max}$ ) and -5 ( $y_{min}$ ), and the midpoint value ( $k$ ) is 0. The amplitude is determined by the following calculation: