(t-1)(t+1) = t^2-1 through the difference of squares rule
So,
(t-1)(t+1)(t^2+1)
(t^2-1)(t^2+1)
(x-1)(x+1) ... let x = t^2
x^2-1 .... another application of the difference of squares rule
(t^2)^2 - 1... plug in x = t^2
t^4 - 1
To compute how many groups of elements we can extract out of a group of elements, we can use the binomial coefficient:
where the factorial is defined as
So, this is the number of possible quintuplet out of 50 numbers:
Similarly, this is the number of possible groups of six numbers out of 60:
So, you win with a combination out of 2118760 in state A, and with a combination every 50063860 in state B this means that winning in state A is easier with a ratio of
Whichi means that winning in state B is 23 times harder
The <em>quadratic</em> equation 3 · x² + 7 · x - 2 = 0 has a <em>positive</em> discriminant. Thus, the expression has two <em>distinct real</em> roots (<em>real</em> and <em>irrational</em> roots).
<h3>How to determine the characteristics of the roots of a quadratic equation by discriminant</h3>
Herein we have a <em>quadratic</em> equation of the form a · x² + b · x + c = 0, whose discriminant is:
d = b² - 4 · a · c (1)
There are three possibilities:
- d < 0 - <em>conjugated complex</em> roots.
- d = 0 - <em>equal real</em> roots (real and rational root).
- d > 0 - <em>different real</em> roots (real and irrational root).
If we know that a = 3, b = 7 and c = - 2, then the discriminant is:
d = 7² - 4 · (3) · (- 2)
d = 49 + 24
d = 73
The <em>quadratic</em> equation 3 · x² + 7 · x - 2 = 0 has a <em>positive</em> discriminant. Thus, the expression has two <em>distinct real</em> roots (<em>real</em> and <em>irrational</em> roots).
To learn more on quadratic equations: brainly.com/question/2263981
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muiplaiclthhuj mujammajan id
(12,-6)
you just multiply it by the dilation factor