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zloy xaker [14]
2 years ago
9

Use the discriminant to describe the roots of each equation. Then select the best description.

Mathematics
1 answer:
Paha777 [63]2 years ago
7 0

The <em>quadratic</em> equation 3 · x² + 7 · x - 2 = 0 has a <em>positive</em> discriminant. Thus, the expression has two <em>distinct real</em> roots (<em>real</em> and <em>irrational</em> roots).

<h3>How to determine the characteristics of the roots of a quadratic equation by discriminant</h3>

Herein we have a <em>quadratic</em> equation of the form a · x² + b · x + c = 0, whose discriminant is:

d = b² - 4 · a · c     (1)

There are three possibilities:

  1. d < 0 - <em>conjugated complex</em> roots.
  2. d = 0 - <em>equal real</em> roots (real and rational root).
  3. d > 0 - <em>different real</em> roots (real and irrational root).

If we know that a = 3, b = 7 and c = - 2, then the discriminant is:

d = 7² - 4 · (3) · (- 2)

d = 49 + 24

d = 73

The <em>quadratic</em> equation 3 · x² + 7 · x - 2 = 0 has a <em>positive</em> discriminant. Thus, the expression has two <em>distinct real</em> roots (<em>real</em> and <em>irrational</em> roots).

To learn more on quadratic equations: brainly.com/question/2263981

#SPJ1

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omeli [17]

The conclusions that can be drawn about f–1(x) are:

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<h3>Calculations and Parameters:</h3>

Given:

f(x) = \frac{-2}{3}x - 24

f(x) + 24 = \frac{-2}{3}x

To find x, we would multiply both sides by -2/3

= x= \frac{-3}{2} (f(x) + 24)

f^-^1(x) = -\frac{3}{2} (0) - 36

f^-^1(x) = -36

Therefore, f^-^1(x)  has an x-intercept of (-36, 0)

Furthermore, f^-^1(x) has a range of all real numbers.

Read more about real numbers here:

brainly.com/question/17020343

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2 years ago
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