12 and 28, because
n + (<u><em>2n + 4</em></u>) = 40
<u><em>3n + 4</em></u> = 40
<em><u>3n = 36 n = 12</u></em>
<u><em>12x2 + 4 = 28</em></u>
<u>28</u> is the larger number.
This is not a full question. If you were given the amount at the begining of 1970 (we'll call it x) and the amount at the end of 1980 (we'll call it y), we should solve them accordingly:
y-x=? (calling the answer a)
a/y=%(not answer yet, call this b)
b+100=answer
5m3 * 7130 kg/m3 = 35650 kg
506 x - 92 y + 90 = 498 - 4 x + 6 y
Geometric figure:
line
y = (255 x)/49 - 204/49
510 x - 98 y - 408 = 0
506 x - 92 y + 90 = 6 (y + 83) - 4 x
Real solution:
y = (255 x)/49 - 204/49
Solution:
y = (255 x)/49 - 204/49
Integer solution:
x = 49 n + 40, y = 255 n + 204, n element Z
Solution for the variable y:
y = 51/49 (5 x - 4)
Answer:
Marc's age is 12
Step-by-step explanation:
Let
x ----> Marc's age
y ---> Tony's age
z ---> Ben's age
we know that
the sum of their ages is 40
so
-----> equation A
Marc is half as old as Tony
so
----> equation B
Marc is three times as old as Ben
so
----> equation C
substitute equation B and equation C in equation A
solve for x
therefore
Marc's age is 12