The dimensions would have to be 20 x 5 as the model holds the same amount for each side, and because 5 is larger than 4 its used as the models stand.
Hope it helps! :)
Answer:
475.
Step-by-step explanation:
We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.
We will use z-score formula and normal distribution table to solve our given problem.

Top 60% means greater than 40%.
Let us find z-score corresponding to normal score to 40% or 0.40.
Using normal distribution table, we got a z-score of
.
Upon substituting our given values in z-score formula, we will get:





Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.
Answer:
when the rest of the variables are held constant
Step-by-step explanation:
Answer:
20
20, 30, 40, 50
I think this might be the answer
3y+21+8y
11y+21 is the answer