What is the rational roots of 4x^3+9x^2-x+10=0
1 answer:
9514 1404 393
Answer:
±1/4, ±1/2, ±1, ±5/4, ±2, ±5/2, ±5, ±10
Step-by-step explanation:
The <em>rational root theorem</em> tells you possible rational roots of this equation would be ...
±(divisor of 10)/(divisor of 4)
The divisors of 10 are 1, 2, 5, 10. The divisors of 4 are 1, 2, 4. Then the possible rational roots are ...
±1/4, ±1/2, ±1, ±5/4, ±2, ±5/2, ±5, ±10
_____
This particular cubic has one irrational real root near -2.689. It has no rational roots.
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<h3>(a) The factor at which the medicine decreased, in 1.5 hour</h3>From the graph, we have the following ordered pairs
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Divide both sides by 270
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<h3>(b) The factor at which the medicine decreased in the first half hour, and the first hour</h3>In (a), we have:
The decay factor (b) to be 0.44
This represents the factor at which the medicine decreased throughout.
Hence, the medicine decrease in the first half hour, and the first hour at a factor of 0.44
<h3>(c) The exponential equation</h3>In (a), we have:
So, the exponential equation is:
In terms of m and h, we have:
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