Answer:
12
Step-by-step explanation:
There are 4 different digits to choose from. Since we want 2-digit number, we will see what digits can we put in place of 1st digit and what digit can we place in place of 2nd digit.
Hence, <u><em>how many digits (from 1,5,6 and 8) can be placed in the 1st digit of the number we want?</em></u>
Any one of the four digits (1,5,6, or 8).
Now, <em><u>How many digits (from 1,5,6 and 8) can be placed as the 2nd digit of the number we want?</u></em>
Any one of the THREE digits (since repetition is not allowed, we disregard the initial digit).
Thus the number of two-digit positive integers is 4 * 3 = 12
Answer:
See Explanation
Step-by-step explanation:
To write an equivalent expression, we can combine like terms. So m +7m is 8 and we get 6(8m+2).
Here are a few others:
48m+12
6(m+m+m+m+m+m+m+m+2)
3(16m+4)
6m+12+42m
6m+6m+6m+6m+6m+6m+6m+6m+2
and the list goes on...
If there are $22 made per hour for 7 hours, you’d add 22 per hour in your table. 1 hour=$22, 2 hours=$44, 3 hours=$66, and so forth. make a table of these numbers up to 7 hours.
I see your last line is : c(x) = 0.9(x^2-10)^2 + 101.1
Let y = x^2, then c(y) = 0.9(y-10)^2 + 101.1
Apparently, c(y) is a parabola, min is 101.1 when y = 10, max is infinity
So let x^2 = 10 -> x = sqrt(10) or -sqrt(10), min is 101.1, max is infinity
If one square is divided into 9 smaller equal squares, then they have to be arranged in 3 lines of 3, that is 3 smaller equal squares per side of the original big square. That said, the area of the big square is equal to the multiplication of 3 small squares sides times 3 small squares sides, call x the length of the small squares.
So,
area = 9 = 3x*3x
9x^2 = 9
x^2 = 1
x = 1
therefore the smaller squares have sides of 1 unit
