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Yuliya22 [10]
2 years ago
13

Evaluate the expression 5(-3) using a number line.​

Mathematics
2 answers:
MArishka [77]2 years ago
7 0

Answer: -15

Step-by-step explanation:

evablogger [386]2 years ago
5 0

Answer:

Compare the treatment of the buffalo by these two groups of people.

Step-by-step explanation:

Native Americans relied heavily on bison for their survival and well-being, using every part of the bison for food, clothing, shelter, tools, jewelry and in ceremoniesNative Americans relied heavily on bison for their survival and well-being, using every part of the bison for food, clothing, shelter, tools, jewelry and in ceremoniesNative Americans relied heavily on bison for their survival and well-being, using every part of the bison for food, clothing, shelter, tools, jewelry and in ceremoniesNative Americans relied heavily on bison for their survival and well-being, using every part of the bison for food, clothing, shelter, tools, jewelry and in ceremoniesNative Americans relied heavily on bison for their survival and well-being, using every part of the bison for food, clothing, shelter, tools, jewelry and in ceremonies

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Find dy/dx for y= x^3 ln (cot x)
ICE Princess25 [194]
<h3>Answer</h3>

  \dfrac{dy}{dx} = 3x^2 \ln(\cot x)-x^3 \csc(x)\sec(x)

<h3>Explanation</h3>

By the product rule (d/dx)(f(x)g(x)) = f(x)g'(x) + g(x)f'(x), we have

  \begin{aligned}\frac{dy}{dx} &= \left(x^3 \ln (\cot x) \right)' \\&= x^3\big(\ln (\cot x)\big)' + \ln (\cot x) \cdot \left(x^3\right)' \end{aligned}

By the chain rule:

  \begin{aligned}\big(\ln (\cot x)\big)' &= \dfrac{1}{\cot x} \cdot (\cot x)' \\ &= \dfrac{1}{\cot x} \cdot -\csc^2 x\\&= -\tan (x) \csc^2(x) \\&= - \frac{\sin x}{\cos x} \cdot \frac{1}{\sin^2 x} = - \frac{1}{\cos x} \cdot \frac{1}{\sin x} \\&= -\csc(x)\sec(x)\end{aligned}

By the power rule:

  (x^3)' = 3x^2

thus

  \begin{aligned}\frac{dy}{dx} &= x^3\big(\ln (\cot x)\big)' + \ln (\cot x) \cdot \left(x^3\right)' \\&= x^3\big( -\csc(x)\sec(x) \big) + \ln(\cot x) \cdot (3x^2) \\&= -x^3 \csc(x)\sec(x) + 3x^2 \ln(\cot x) \\&= 3x^2 \ln(\cot x)-x^3 \csc(x)\sec(x)\end{aligned}

Nothing to do to simplify any further, other than factoring out x^2.

4 0
3 years ago
Simplify the following expression. 4a^-2b<br><br> A.) b/4a^2<br> B.)4b/a^2<br> C.)1/4a^b2
Sergio [31]
ANSWER

The correct answer is B

\frac{4b}{ {a}^{2} }


EXPLANATION

The given exponential expression is

4 {a}^{ - 2} b

We can rewrite this as,

4b \times  {a}^{ - 2}

We need to simplify to obtain a positive index, so we apply the following property,


{a}^{ - m}  =  \frac{1}{ {a}^{m} }

This implies that,


4b \times  {a}^{ - 2}  = 4b \times  \frac{1}{ {a}^{2} }

This will finally simplify to,

4b \times  {a}^{ - 2}  =\frac{4b}{ {a}^{2} }


Therefore the correct answer is B
6 0
3 years ago
Read 2 more answers
Does anyone know what 1+1 is?
hammer [34]

1+1 = 2  that is the answer


6 0
2 years ago
Read 2 more answers
Solve the variable<br> -10+ s/1.5= -5
patriot [66]

Answer:

s = 15 over 2 (15/2 fraction) or 7.5

3 0
2 years ago
Mrs. Bautista invested Php2700.00 part at 8% and the rest at 11% .How musch did she invest at each rate if her total annual inco
Margarita [4]

Answer:

The answer to the question is

She invested

Php2700.00 at 8 % and

Php 20,400.00 at 11 %

Step-by-step explanation:

To solve the question we note that

Simple interest is given by \frac{P*R*T}{100} where

P= Principal, R = Rate and T = Time

If we call the first part P₁, T₁,  and R₁ and the second part

P₂, T₂,  and R₂

Then {P_1*(1+R_1*T_1}) +{P_*(1+R_2*T_2})  = 2460.00

= 2700×0.08×1 + P₂×0.11×1 = 2460  which gives

2244÷0.11 = P₂ or P₂ = Php 20,400.00

That is she invested

Php2700.00 at 8 % and

Php 20,400.00 at 11 %

5 0
2 years ago
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