Answer:

Step-by-step explanation:
Hint- First we have to calculate the mean and standard deviation of the sample and then applying formula for confidence interval we can get the values.
Mean of the sample is,

Standard deviation of the sample is,

The confidence interval will be,

Here,
Z for 95% confidence interval is 1.96, and n is sample size which is 24.
Putting the values,



Confidence interval is used to express the degree of uncertainty associated with a sample.
95% confidence interval means that if we used the same sampling method to select different samples and calculate an interval, we would expect the true population parameter to fall within the interval for 95% of the time.
You need 105 children to meet the minimum.
Answer:
This is false.
Step-by-step explanation:
90 + 12 = 102.
6(15+12) equals to 6(27) which is 162.
By solving for x you get x=6
<span>6 002 310.583
Six million and two thousand three hundred and ten point five eight three.
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