Help plzzz Thank you smmmm!

|x-1| if x>1<br> how do you simplify this

JulsSmile [24]

Use the definition of absolute value.

$|x| = \begin{cases} x & \text{if } x \ge0 \\ -x & \text{if } x < 0 \end{cases}$

The absolute value is always non-negative. So if $x$ is already non-negative, $|x|=x$ is unchanged. But if $x$ is negative, then $|x|=-x$ because multiplying $x$ by -1 makes it positive.

Now, if $x>1$ , then by the definition of absolute value,

$x > 1 \implies x - 1 > 0 \implies \boxed{|x - 1| = x - 1}$

4 0

2 years ago

Which rational number is one tick mark to the left of -3/4

Zolol [24]

I'm assuming each tickmark is 1/4 = 0.25

If that assumption is correct, then going one tickmark to the left of -3/4 lands you on -4/4 which simplifies to -1.

So -1 is one tickmark to the left of -3/4

Again, this all hinges on the assumption that each tickmark is 1/4 a unit away from its neighbor.

5 0

3 years ago

Select the correct answer. The radius of a nitrogen atom is 5. 6 × 10-11 meters, and the radius of a beryllium atom is 1. 12 × 1

Grace [21]

A negative exponent means the number of the exponent divide by the number. The the radius of beryllium atom is larger than the radius of a nitrogen atom by two times.

Given information-

The radius of a nitrogen atom is $5.6\times10^{-11}$ meters.

The radius of a beryllium atom is $1.12 \times10^{-10}$ meters

<h3>Negative exponents</h3>

A negative exponent means the number of the exponent divide by the number.

As the radius of the nitrogen atom is $5.6\times10^{-11}$ meters. Convert it in the power of negative exponent of 10.

Let the radius of the nitrogen is $r$ mm. Thus,

$r=5.6\times 10^{-11}\\
r=5.6\times 10^{-10-1}\\
r=5.6\times 10^{-10}\times10^{-1}\\
r=\dfrac{5.6\times 10^{-10}}{10} \\
r=0.56\times 10^{-10}$

Now the base of the exponents of both the atoms are same. As the radius of the nitrogen atom is $0.56\times 10^{-10}$ meters and the radius of the beryllium atom is $1.12 \times10^{-10}$ . Thus the radius of beryllium atom is larger.

To calculate how many times, the radius of beryllium atom should be divided by the radius of a nitrogen atom. Thus,

$=\dfrac{1.12\times10^{-10}}{0.56\times10^{-10}} \\
=2$

Thus the the radius of beryllium atom is larger than the radius of a nitrogen atom by two times.

Learn more about the negative exponents here;

https://brainly.in/question/1221452

7 0

3 years ago

A scrap metal buyer pays $3.18 per square foot of steel.

trapecia [35]

Answer:

2*3 = 6

3.18*6 = $19.08

Lidless is going to be around $16

8 0

3 years ago

Anyone? Please I need help!!

JulsSmile [24]

Answer:

the correct choice is marked

Step-by-step explanation:

Let x represent the smaller number. Then the larger number is 8x, and the difference is ...

8x -x = 280

7x = 280 . . . . . simplify

x = 40 . . . . . . divide by 7

The larger number is 8x = 8(40) = 320.

_____

<em>Additional comment</em>

Effectively, we have solved for the multiplier (40) that gives the ratio with 320 on top and a difference between top and bottom of 280:

$\dfrac{8}{1}=\dfrac{8\cdot40}{1\cdot40}=\dfrac{320}{40}$

4 0

2 years ago

Help plzzz Thank you smmmm! ​

Help plzzz Thank you smmmm!