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Sonbull [250]
3 years ago
8

What is the area of the triangle shown below ​

Mathematics
2 answers:
Anika [276]3 years ago
4 0
The answer is 84 because 14 x 6= 84
lyudmila [28]3 years ago
3 0

Answer:

90 x 4 x 6

Step-by-step explanation:

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Thomas deposited $800 into two different accounts.
Mazyrski [523]
I’d go with D, you do 350 and multiply it by 0.0425 and do the same with 450 and multiply by 0.0425 and you multiply each of those answers and then add them to 800
7 0
2 years ago
Round 637.892 to whole number
Stels [109]

Answer:

638

Step-by-step explanation:

its 638, not 639 because its above 638.5

4 0
3 years ago
Read 2 more answers
Can you please answer the question? Thank you so much.
pychu [463]

Answer:

bruh

Step-by-step explanation:

4 0
3 years ago
Help with 5b please . thank you.​
Allushta [10]

Answer:

See explanation

Step-by-step explanation:

We are given f(x)=ln(1+x)-x+(1/2)x^2.

We are first ask to differentiate this.

We will need chain rule for first term and power rule for all three terms.

f'(x)=(1+x)'/(1+x)-(1)+(1/2)×2x

f'(x)=(0+1)/(1+x)-(1)+x

f'(x)=1/(1+x)-(1)+x

We are then ask to prove if x is positive then f is positive.

I'm thinking they want us to use the derivative part in our answer.

Let's look at the critical numbers.

f' is undefined at x=-1 and it also makes f undefined.

Let's see if we can find when expression is 0.

1/(1+x)-(1)+x=0

Find common denominator:

1/(1+x)-(1+x)/(1+x)+x(1+x)/(1+x)=0

(1-1-x+x+x^2)/(1+x)=0

A fraction can only be zero when it's numerator is.

Simplify numerator equal 0:

x^2=0

This happens at x=0.

This means the expression,f, is increasing or decreasing after x=0. Let's found out what's happening there. f'(1)=1/(1+1)-(1)+1=1/2 which means after x=0, f is increasing since f'>0 after x=0.

So we should see increasing values of f when we up the value for x after 0.

Plugging in 0 gives: f(0)=ln(1+0)-0+(1/2)0^2=0.

So any value f, after this x=0, should be higher than 0 since f(0)=0 and f' told us f in increasing after x equals 0.

8 0
2 years ago
You invest $1,050.00, buying stock in a company at $10.00/share. The shares increase in value by 13% the first year and decrease
allochka39001 [22]
Number of shares
1050/10=105
After one year share value
10×(1+0.13)=11.3
After the second year share value
11.3×(1−0.05)=10.735
Total
10.735×105=1,127.175
3 0
3 years ago
Read 2 more answers
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