Hi there!
Let r be the number of matches that Rebecca's team won.
We know that Katheryn's team won 9 more matches than Rebecca's team, and we know that Katheryn's team won 52 matches.
Using this given information, we can create the following equation.

If you wish to solve this, we can subtract both sides by 9 to get the following value for r.

Have an awesome day! :)
~collinjun0827, Junior Moderator
![\bf \cfrac{(x-2)(x+3)}{2x+2}\implies \cfrac{x^2+x-6}{2x+2}~~ \begin{array}{llll} \leftarrow \textit{2nd degree polynomial}\\ \leftarrow \textit{1st degree polynomial} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{vertical asymptote}}{2x+2=0}\implies 2x=-2\implies x=-\cfrac{2}{2}\implies x=-1](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B%28x-2%29%28x%2B3%29%7D%7B2x%2B2%7D%5Cimplies%20%5Ccfrac%7Bx%5E2%2Bx-6%7D%7B2x%2B2%7D~~%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cleftarrow%20%5Ctextit%7B2nd%20degree%20polynomial%7D%5C%5C%20%5Cleftarrow%20%5Ctextit%7B1st%20degree%20polynomial%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bvertical%20asymptote%7D%7D%7B2x%2B2%3D0%7D%5Cimplies%202x%3D-2%5Cimplies%20x%3D-%5Ccfrac%7B2%7D%7B2%7D%5Cimplies%20x%3D-1)
when the degree of the numerator is greater than the denominator's, then it has no horizontal asymptotes.
quick note:
when the degree of the numerator is 1 higher than the degree of the denominator, then it has an slant-asymptote, so this one has a slant-asymptote.
Answer:
100
Step-by-step explanation:
100
Answer:
-0.0777026243 A^5
Step-by-step explanation:
Answer:
The company can manufacture 135 boxes of stuffed animals for $5000
Step-by-step explanation:
To find b, substitute $5000 for c(x), so
Then subtract 2300 from both sides of the equation, so
- 5000 (-2300) = 20b + 2300 (-2300)
- 2700 = 20b
Finally divide both sides of the equation by 20, so
To check your answer substitute 135 in as b...
- c(x) = 20(135) + 2300
- c(x) = 5000