The first expression could be written as 3x + 12 and the second could be written as 2x + 6.
In order to find these, count the number of x's you see in each question. Then use that number as the coefficient to x in your statement. The first problem has 3 and the second has 2.
Then add the numbers of 1's together to get the constants at the end of the expressions. The first has 12 and the second has 6.
1/7 of 42 is smaller. 47/7= 6 < 18 = 36/2
I perfer the the gx are square root of the output
