Answer:
String word = "George slew the dragon";
int pos = word.indexOf("dr");
String drWord = word.substring(pos, pos+4);
System.out.println(drWord);
Explanation:
Assuming dr is always there, we don't have to check the validity of 'pos'. Normally, you would!
Answer/Explanation:
It is best to use Performance Monitor and Process counters to observe performance.
Cheers
the answer to this is 2 and 3
Hope this helped
-scav
Answer:
Explanation:
The following code is written in Python. It asks the user for an input. Then cleans the input using regex to remove all commas, whitespace, and apostrophes as well as making it all lowercase. Then it reverses the phrase and saves it to a variable called reverse. Finally, it compares the two versions of the phrase, if they are equal it prints out that it is a palindrome, otherwise it prints that it is not a palindrome. The test case output can be seen in the attached picture below.
import re
phrase = input("Enter word or phrase: ")
phrase = re.sub("[,'\s]", '', phrase).lower()
reverse = phrase[::-1]
if phrase == reverse:
print("This word/phrase is a palindrome")
else:
print("This word/phrase is NOT a palindrome")
I would say two car length rule. I am not sure what the official license rule is or if it has been changed, but originally the rule was 3 seconds usually depending on how fast the car is going. The faster you are going, the longer it takes to stop. So two-car length rule would probably be the best choice. Definitely not A.