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Monica [59]
2 years ago
8

How do i do this i need it now

Mathematics
1 answer:
sveticcg [70]2 years ago
6 0

Answer:

what is the question??

i can answer if i had the question

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PLEASE HELP ASAP!!
BabaBlast [244]

Answer:

The first term of the sequence is -120.

Step-by-step explanation:

The formula for the "nth" term of a geometric sequence is shown below:

an = a0*r^(n-1)

Where an is the nth term, r is the ratio and n is the position of the term on the sequence. For this problem we want to find what is the initial term, a0, so we will isolate it in the formula as shown below:

a0*r^(n-1) = an

a0 = an/[r^(n-1)]

We then apply the data given to us

a0 = 31.45728/[-0.8^(7-1)]

a0 = 31.45728/[-0.8^6] =31.45728 /-0.262144= -120

The first term of the sequence is -120.

4 0
3 years ago
PLS PLS PLS HELP ME ILL GIVE 20 points.
lisov135 [29]

Answer:

if you want to know the x is.

Step-by-step explanation:

(180°-4x)+(180°-6x)+2x=180°

x=22.5°

8 0
2 years ago
Ummm i know both of these are easy but i can't remember them please help
ExtremeBDS [4]
It is 4 because 3 times 4 equals 12
4 0
3 years ago
In an 80/20 mortgage, what is the second mortgage used for?
avanturin [10]

Answer:

The first loan covers 80 percent of the home’s price, while the second covers the remaining 20 percent.

Step-by-step explanation:

they are still a home price percentage

5 0
3 years ago
Read 2 more answers
The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula mc
Gnoma [55]
<span>Given that the orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P = a^(3/2). If Saturn’s orbital period is 29.5 years, then 29.5 = a^(3/2) a = (29.5)^(2/3) = 9.547 Therefore, Saturn's distance from the sun is 9.547 astronomical units.</span>
7 0
2 years ago
Read 2 more answers
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