Answer:
<em>Equation:
</em>
<em>HCL + HCL = HCL
</em>
<em><u>0.30x + 0.45(50-x) = 0.35*50
</u></em>
<em><u>Multiply thru by 100 to get:
</u></em>
<em><u>30x + 45*50 - 45x = 35*50</u></em>
<em><u>-15x = -10*50
</u></em>
<em><u>x = (2/3)50
</u></em>
<em><u>x = 33 1/3 liters (amt. of 30% solution needed in the mixture)
</u></em>
<em><u>50-x = 16 2/3 liters (amt. of 45% solution needed in the mixture)
</u></em>
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Step-by-step explanation:
If it was 25%, it would be a 90 degree angle. So we can calculate this using a proportion. 25/90 = 24/x. Cross multiply to get 25x = 2160. When you divide by 25 on both sides you get 86.4. So the angle should be 86 degrees. Hope this helps.
Answer:
76°
Step-by-step explanation:
![\because \: m \angle \: 1 = m \angle \: 12 \\ (exterior \: alternate \: \angle s) \\ \\ \therefore \: (5x + 44) \degree = (8x + 8) \degree \\ \\ \therefore \: 5x + 44 = 8x + 8 \\ \\ 5x - 8x = 8 - 44 \\ \\ - 3x = - 36 \\ \\ x = \frac{ - 36}{ - 3} \\ \\ \huge \red{x = 12} \\ \\ \because \: m \angle \: 12 = (8x + 8) \degree \\ \\ \therefore \: m \angle \: 12 = = (8 \times 12 + 8) \degree \\ \\ \therefore \: m \angle \: 12 = = (96+ 8) \degree \\ \\ \therefore \: \purple{m \angle \: 12 = 104 \degree} \\ \\ \because \: m \angle \: 10 + m \angle \: 12 = 180 \degree \\(linear \: pair \: \angle s) \\ \\ \therefore \: m \angle \: 10 + 104 \degree = 180 \degree \\ \\ \therefore \: m \angle \: 10 = 180 \degree - 104 \degree \\ \\ \huge \orange{ \boxed{\therefore \: m \angle \: 10 = 76 \degree }}](https://tex.z-dn.net/?f=%20%5Cbecause%20%5C%3A%20m%20%5Cangle%20%5C%3A%201%20%3D%20m%20%5Cangle%20%5C%3A%2012%20%5C%5C%20%28exterior%20%5C%3A%20alternate%20%5C%3A%20%20%5Cangle%20s%29%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20%285x%20%2B%2044%29%20%5Cdegree%20%3D%20%288x%20%2B%208%29%20%5Cdegree%20%5C%5C%20%20%5C%5C%20%5Ctherefore%20%5C%3A%205x%20%2B%2044%20%3D%208x%20%2B%208%20%5C%5C%20%20%5C%5C%205x%20-%208x%20%3D%208%20-%2044%20%5C%5C%20%20%5C%5C%20%20-%203x%20%3D%20%20-%2036%20%5C%5C%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B%20-%2036%7D%7B%20-%203%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Chuge%20%5Cred%7Bx%20%3D%2012%7D%20%5C%5C%20%20%5C%5C%20%20%20%5Cbecause%20%5C%3A%20m%20%5Cangle%20%5C%3A%2012%20%20%3D%20%288x%20%2B%208%29%20%5Cdegree%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20m%20%5Cangle%20%5C%3A%2012%20%20%3D%20%3D%20%288%20%5Ctimes%2012%20%2B%208%29%20%5Cdegree%20%20%5C%5C%20%20%5C%5C%20%5Ctherefore%20%5C%3A%20m%20%5Cangle%20%5C%3A%2012%20%20%3D%20%3D%20%2896%2B%208%29%20%5Cdegree%20%20%5C%5C%20%20%5C%5C%20%5Ctherefore%20%5C%3A%20%20%5Cpurple%7Bm%20%5Cangle%20%5C%3A%2012%20%20%3D%20104%20%5Cdegree%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Cbecause%20%5C%3A%20m%20%5Cangle%20%5C%3A%2010%20%2B%20m%20%5Cangle%20%5C%3A%2012%20%20%3D%20180%20%5Cdegree%20%5C%5C%28linear%20%5C%3A%20pair%20%5C%3A%20%20%5Cangle%20s%29%20%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20m%20%5Cangle%20%5C%3A%2010%20%2B%20104%20%5Cdegree%20%3D%20180%20%5Cdegree%20%5C%5C%20%20%5C%5C%20%5Ctherefore%20%5C%3A%20m%20%5Cangle%20%5C%3A%2010%20%3D%20180%20%5Cdegree%20%20-%20104%20%5Cdegree%20%5C%5C%20%20%5C%5C%20%20%5Chuge%20%5Corange%7B%20%5Cboxed%7B%5Ctherefore%20%5C%3A%20m%20%5Cangle%20%5C%3A%2010%20%3D%2076%20%5Cdegree%20%7D%7D)
Average change in d(t) = (350-126) / (5-3) = 112 m/s
This represents the average speed of the object during the 2 second period between t = 3 and t = 5.
1. "the sum of -4x and 2 is 9"? -4x + 2 = 9
Answer:
A.-4x + 2 = 9
2. solve x - 6 = -18
x = -18 +6
x = -12
Answer is B.x = -12
3. solve 4x + 3 = 47
4x = 47 -3
4x = 44
x = 44/44 = 11
Answer is A.x = 11
4. solve 1/3x = 12
x= 12 / (1/3)
x = 12 * 3 = 36
Answer is C.x = 36
5. solve 3x + 3 = 21
3x = 21 -3
3x = 18
x = 18/3 = 6
Answer is B.x = 6
6. solve. 3/2x - 4 = 16
3/2x = 16 + 4
3/2x =20
x = 20 / (3/2)
x = 20 * 2/3
x = 40/3
A.x = 13 1/3
Answer is B.x = 13 1/3