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photoshop1234 [79]

3 years ago

8

To make green paint, students mixed yellow paint with blue paint. The table below shows how many yellow and blue drops from a dr

opper several students used to make the same shade of green paint. Complete the table.

1 answer:

lesya692 [45]3 years ago

4 0

I know that the first box on the right would be 8 3/4 but I’m unsure about the rest

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Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago

given the equation y = 2x - 8, find the ordered-pair solution when x = 4 and the ordered-pair solution when y = 4

babunello [35]

Answer:

When x = 4, (4, 0)

When y = 4, (6, 4)

Step-by-step explanation:

To find the ordered-pair solution when x = 4, plug 4 into the x of the equation.

y = 2x - 8

y = 2(4) - 8

y = 8 - 8

y = 0

This produces the ordered pair (4, 0).

To find the ordered-pair solution when y = 4, plug 4 into the y of the equation.

y = 2x - 8

4 = 2x - 8

12 = 2x

6 = x

x = 6

This produces the ordered pair (6, 4).

6 0

3 years ago

Concept Check: Sketch each angle in standard position. Draw an arrow representing the correct amount of rotation. Find the measu

soldi70 [24.7K]

Step-by-step explanation:

...............

......

8 0

2 years ago

In a recent snail race, a snail traveled a distance of 1 1/6 inches in 2 minutes. Find the number if inches traveled per minute

Alecsey [184]

Answer:

For inch/min =0.9167 inch/min

For min/inch = 1.0908 min/inch

Step-by-step explanation:

The snail in the race traveled 11/6 inches in 2 minutes.

The number of inches per minute is equal to = (11/6)/(2)

= 11/12

=0.9167 inch/min

The number of minutes per inch is equal to = 1/(inch per min)

= 1/0.9167

= 1.0908 min/inch

Minutes per inch is gotten by taking the inverse of inch/min or dividing the number of minutes by number of inches

6 0

3 years ago

How do you do a and b on this problem

gogolik [260]

for a all you have to do is * you will find the answer. for b what ever yo answer was for a u will put that for the hours n what u had * u put for min for seconds

8 0

3 years ago