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photoshop1234 [79]

2 years ago

8

To make green paint, students mixed yellow paint with blue paint. The table below shows how many yellow and blue drops from a dr

opper several students used to make the same shade of green paint. Complete the table.

1 answer:

lesya692 [45]2 years ago

4 0

I know that the first box on the right would be 8 3/4 but I’m unsure about the rest

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HELP PLS. Due in 10 mins

sertanlavr [38]

Answer:

1. Linear

2. Not Linear

3. Linear

4. Linear

Step-by-step explanation:

<u>Function 1</u>

Linear, follow a sequence of 4, 3

<u>Function 2</u>

Not Linear, does not follow a sequence

<u>Function 3</u>

Linear, follow a sequence of 1, 0

<u>Function 4</u>

Linear, follow a sequence of 3, -1

7 0

2 years ago

David swam in 312 events during the last 6 years. He swam the same number of events each year.

natta225 [31]

Answer:

52

Step-by-step explanation:

Divide 312 by 6 to find the number of events he swam per year

5 0

2 years ago

Read 2 more answers

Complete the ordered pair.<br> The graph of y= sin(2x - 1) passes through the point (___,0).

Westkost [7]

Answer:

(0.5,0)

Step-by-step explanation:

Input the equation into a graphing calculator

4 0

3 years ago

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

3 years ago

What point on the line y=9x+8 is closest to the origin

Marat540 [252]

to find the point, find the location

realize that the shortest line that crosses through the origin and y=9x+8 is perpendicular to y=9x+8

perpendicular lines have slopes that multiply to get -1

y=9x+8 has a slope of 9

9*m=-1, m=-1/9

the slope of the mystery line is -1/9

since it passes through the origin, the y intercept is 0

y=(-1/9)x is the equation of the line from the point to the origin

find the intersection of this line and the original line

set them equal to each other

(-1/9)x=9x+8

multily both sides by 9

-x=81x+72

minus 81 both sides

-82x=72

divide both sides by -82

x=-36/41

find y

y=(-1/9)x

y=(-1/9)(-36/41)

y=4/41

the point is $(\frac{-36}{41},\frac{4}{41})$

3 0

2 years ago