In the largest triangle, the missing side has length
√((11 + 5)² - <em>x</em> ²) = √(256 - <em>x</em> ²)
But it's also the hypotenuse of the triangle with side lengths 11 and <em>y</em>, so that its length can also be written as
√(11² + <em>y</em> ²) = √(121 + <em>y</em> ²)
so that
√(256 - <em>x</em> ²) = √(121 + <em>y</em> ²)
or, by taking the squares of both sides,
256 - <em>x</em> ² = 121 + <em>y</em> ²
<em>y</em> ² = 135 - <em>x</em> ²
In the smallest triangle, you have
5² + <em>y</em> ² = <em>x</em> ² ==> <em>x</em> ² = 25 + <em>y</em> ²
Substitute this into the previous equation and solve for <em>y</em> :
<em>y</em> ² = 135 - (25 + <em>y</em> ²)
<em>y</em> ² = 110 - <em>y</em> ²
2<em>y</em> ² = 110
<em>y</em> ² = 55
<em>y</em> = √55
Well if you were to draw a number line from 0 to 2, 9/10 will be placed right before 1. 10/9 will be placed after one. Wendy jumped the shorter distance.
Hello, hope this makes some sense, the midpoint formula is what’s given in the picture and the rest is just substitution
Round fraction as a decimal: 6/13=.462 that's the answer
