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ExtremeBDS [4]
3 years ago
5

NEED HELPPPPPPP ASAPPPP PLSSSS REWARD BRAINLIESTT!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Answer:

4)x=2

5) (-3,4)

Step-by-step explanation:

4) f(x)=x^2-4x+4-4+5

f(x)=(x-2)^2+1

f(x)=a(x-h)^2+k

Axis of symmetry is x=h

h is 2, so axis of symmetry is x=2

5) f(x)=x^2+6x+9-9+13

f(x)=(x+3)^2+4

f(x)=a(x-h)^2+k

Vertex is (h,k)

So, vertex is (-3,4)

Sorry, I can't answer the first 3, cause I don't understand what a-value, b-value and c-value mean.

And also is this college math, cause I'm in middle-school, and I know how to do it.

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Please help me need help me please please help me
Reil [10]

9514 1404 393

Answer:

  (3)  y = (x -3)²

Step-by-step explanation:

Try the first value of x in each function:

  (1)  y = 3² -3 ≠ 0

  (2)  y = (3 +3)² ≠ 0

  (3)  y = (3 -3)² = 0 . . . . . . matches the table value for f(3)

  (4)  y = 3² +3 ≠ 0

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The only viable choice is (3).

5 0
3 years ago
2. (01.02 MC)<br> Find the value of the expression 4a4 – 2b2 + 40 when a = 2 and b = 7. (5 points)
Sergio039 [100]

Answer:

4x2x4 - 2×7×2 + 40

64 - 28 + 40=76

6 0
3 years ago
Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.
Tems11 [23]

Answer:

The area of the triangle is  \sqrt{3}

Step-by-step explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle  ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is  = \frac{1}{2}(base \times height)

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE  = \sqrt{(0-1)^2 + (0-1)^2}

DE =\sqrt{(-1) ^2 + (-1)^2

DE = \sqrt{1+1}

DE = \sqrt{2}

Base = \sqrt{2}

Height is DF

DF =tan(60^{\circ}) \times DE

DF = \sqrt{3} \times DE

DF = \sqrt{3} \times\sqrt{2}

Now, the area of the triangle is

= \frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})

=\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})

=\frac{1}{2}(2\sqrt{3} )

=\sqrt{3}

6 0
3 years ago
PLZ ANSWER THIS ITS DUE TODAY I WILL GIVE BRAINLEST!!!!
Sever21 [200]

Answer:

In many instances, the lyrics to folk songs came from existing nursery rhymes or poems, and some of the nursery rhymes had variations, depending on region or time. Thus, these folk songs may have lyrics that are slightly different from those you are familiar with.

Therefore, in my opinion, I think that Nursery songs can be considered folk music.

Im so so so so sorry if this is wrong or not the answer you were looking for. i truly am. hopefully this will be good

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
In one region, the september energy consumption levels for single-family homes are found to be normally distributed with a mean
tatyana61 [14]
The probability would be 0.1971.

We will calculate a z-score for each end of this interval.

z = (X-μ)/σ

For the lower limit:
z = (1100-1050)/218 = 50/218 = 0.23

For the upper limit:
z = (1225-1050)/218 = 175/218 = 0.80

Using a z-table (http://www.z-table.com) we see that the area under the curve to the left of, less than, the lower limit is 0.5910.  The area under the curve to the left of, less than, the upper limit is 0.7881.  To find the area between them, we subtract:

0.7881 - 0.5910 = 0.1971
6 0
3 years ago
Read 2 more answers
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