3 years ago

Let g(x) = (x - 2)2. Find x such that g(x) = 25.

Mathematics

2 answers:

pentagon [3]3 years ago

8 0

Answer:

x = 14.5

can also be written as;

x = 29/2

Step-by-step explanation:

GarryVolchara [31]3 years ago

3 0

The answer 14.5 I THINKKK

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The point slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y-1- 1-12). What is the standard fo

kirill [66]

The point-slope form of the equation through those points is
.. y -1 = (1/4)(x -12)
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Add 8 to put into standard form
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3 years ago

What is 11.15×20.78?

Novosadov [1.4K]

Simplify 15*20 to 300

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3 years ago

Raheem's entire workout consisted of 15 minutes of warm-up exercises, 30 minutes of lifting weights,and 45 minutes on the treadm

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4 0

3 years ago

Anyone know this answer??

satela [25.4K]

6+10+3+8 = 27, so they played a total of 27 games

6/10 reduces to 3/5 for home games

5 0

3 years ago

Read 2 more answers

Solve the equation using the quadratic formula : x^2-10x+25=18

Sever21 [200]

$x^2-10x+25=18 \\ \\x^2-10x+25-18 = 0\\ \\ x^2-10x+ 7 =0 \\ \\a=1 , b = -10 , c= 7 \\ \\ \Delta = b^{2}-4ac = (-10)^{2}-4*1*7=100-28 = 72 \\ \\\sqrt{\Delta }=\sqrt{72}= \sqrt{2*36} =\sqrt{36}*\sqrt{2} =6\sqrt{2}$

$x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{10- 6\sqrt{2}}{2}=\frac{2(5-3\sqrt{2})}{2}= 5-3\sqrt{2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{10+ 6\sqrt{2}}{2}=\frac{2(5+3\sqrt{2})}{2}= 5+3\sqrt{2}$

$Answer : \ x= 5-3\sqrt{2} \ \ or \ \ x = 5+3\sqrt{2}$

8 0

3 years ago