7. The pair of polygons is similar. Find the value of x.

1 answer:

4 0

The polygons are said to be similar if and only if the ratio of the measures of their corresponding sides are equal. If we are to establish the equation by the definition given above that would be,

15/10 = 60/x

The value of x from the equation is 40. Hence, the side measures 40.

ANSWER: 40

The answer is the last choice.

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Can anyone figure this out for me please? It would be greatly appreciated.

Ira Lisetskai [31]

Check the picture below.

now, to get how much is the area of the tiled section, we simply get the area of the whole pool, 53x26, which includes the tiles, and then subtract the area without the tile, the rectangle in the middle, and what's leftover, is the area of the tiled area.

$\bf 53-4\frac{1}{2}-4\frac{1}{2}\implies 53-9\implies \boxed{42}
\\\\\\
26-4\frac{1}{2}-4\frac{1}{2}\implies 26-9\implies \boxed{17}
\\\\\\
\textit{so the area of the rectangle in the middle is}\implies 42\cdot 17\implies 714
\\\\\\
\textit{and the area of the whole pool is}\implies 53\cdot 26\implies 1378$

$\bf \stackrel{\textit{area of the whole pool}}{1378}~~-~~\stackrel{\textit{area of the middle rectangle}}{714}\implies \stackrel{\textit{area of the tiles}}{664}\\\\
-------------------------------\\\\
\textit{we know that is }\$5\frac{1}{2}\textit{ for a foot of tile, then}\stackrel{\textit{price of the tiles}}{664\cdot 5\frac{1}{2}}\implies 3652$

8 0

3 years ago

2/3 gas tank cuts 3 lawns how many does 1 gas tank cut

postnew [5]

(2/3) / 3 = 1/x...2/3 to 3 lawns = 1 to x lawns
cross multiply
(2/3)(x) = (3)(1)
2/3x = 3
x = 3 * 3/2
x = 9/2 or 4 1/2 lawns can be cut with a full tank of gas

8 0

2 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$