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3 years ago

The sum of x and 16 is less than 32

Mathematics

1 answer:

OleMash [197]3 years ago

5 0

I'm unsure of the question but this expression can be written as:
16 + x < 32.
This can be simplified to:
x < 16

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Korolek [52]

The answer is A.....

5 0

3 years ago

Graph the line with slope -1/3 passing through the point (2, 1).

bogdanovich [222]

Answer:

Step-by-step explanation:

y = mx + b

y = -x/3 + b

1 = -2/3 + b

b = 5/3

y = -x/3 + 5/3

5 0

2 years ago

Maureen worked 48 hours last week. Her hourly rate is $8.00. Maureen’s gross pay for last week was $

snow_lady [41]

1 hour = $8.00

48 hours = $8 x 48
48 hours = $384

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Answer: $384
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8 0

3 years ago

Angelina_Jolie [31]

9514 1404 393

Answer:

x = 8

Step-by-step explanation:

Corresponding segments are proportional.

(3x +1)/10 = (7x -1)/22

11(3x +1) = 5(7x -1) . . . . . . multiply by 110

33x + 11 = 35x -5 . . . . . . eliminate parentheses

16 = 2x . . . . . . . . . . . add 5-33x to both sides

8 = x . . . . . . . . . . divide by 2

3 0

3 years ago

Read 2 more answers

There are three different cubes such that the first cube is 64 times the volume of the second, and the volume of the second cube

tankabanditka [31]

Answer:

4/3

Step-by-step explanation:

If the ratio between the volumes of the first and the second cube is 64, the ratio between the sides is the cubic root of the ratio between the volumes, so:

$V1 / V2 = 64$

$s1 / s2 = \sqrt[3]{64} = 4$

Doing the same for the second and third cubes, we have:

$V2 / V3 = 1/27$

$s2/ s3 = \sqrt[3]{1/27} = 1/3$

So the ratio of the first cube side and the third cube side is:

$s1 / s3 = (s1/s2) * (s2/s3) = 4 * (1/3) = 4/3$

5 0

3 years ago