Uhh..not in a mood for a meet, k? Maybe later hun~~
We will use distribution
we will multiply 6 to each variable and number in the parenthesis.
6 times x plus 6 times 4
which is 6x +24
Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important
6d^4+4d^3-6d^2-4d
undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of 2 perfect squares
(2d)(d-1)(d+1)(3d+2)
77.
group
(45z^3+20z^2)+(9z+4)
factor
(5z^2)(9z+4)+(1)(9z+4)
undistribuet (9z+4)
(5z^2+1)(9z+4)
Answer:
-33
Step-by-step explanation:
well you can use mid point formula and solve for x
or count how many it takes to get from -3 to 27 and add that to -3 the other direction
