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Dafna11 [192]
3 years ago
13

HELP ASASP ITS 6Th GRADE MATH

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0

Answer:

We are learning this in 7th grade lol how did you get 7th grade math to 6th grade math

You might be interested in
How many 1/2's are in 5 1/2?
KatRina [158]

Answer:

11

Step-by-step explanation:

1/2 * 2 = 1, 5 1/2 * 2 = 11.

7 0
3 years ago
Each side of a rectangular prism measures 2 inches, and the height is 10 inches. What is the volume?
Diano4ka-milaya [45]
V=lwh
evidently, l=w=2

so
h=10
l=2
w=2

v=2*2*10=40

answer is 40 in^3
6 0
3 years ago
A sequence of transformations was applied to an equilateral triangle in a coordinate plane. The transformations used were rotati
Svetlanka [38]

Answer:

A- It must be an equilateral triangle with the same side lengths as the original triangle

Step-by-step explanation:

Well The Equilateral Triangle dont change at all But its position on the coordinate plane changes, So it must be still a Equilateral Triangle.

The other options are talking about how the equilateral triangle changes, But it not true only the positions on the coordinate plane changes.

6 0
3 years ago
3.If ABCD is a parallelogram with AB = 2x + 1, AD = x + 13, and DC = 3x -11. Determine if ABCD is
madam [21]

Answer:

  ABCD is a rhombus

Step-by-step explanation:

Sides AB and DC are opposite and equal in parallelogram ABCD. This means ...

  AB = CD

  2x +1 = 3x -11

  12 = x . . . . . . . . add 11-2x to both sides

Sides AB and CD have length ...

  2x +1 = 2(12) +1 = 24 +1 = 25

Then the length of side AD is ...

  AD = x +13 = 12 +13 = 25

Adjacent sides AB and AD of the parallelogram have the same length, The figure is a rhombus.

3 0
2 years ago
What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?
ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

6 0
3 years ago
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