Answer:
1) 402.7 grams. This estimate is called the sample mean.
2) (399.11, 406.29)
3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.
I am 99% sure that the value lies between 399.11 grams and 406.29 grams.
Explanation:
sample size (n) = 40, the mean weight (x)= 402.7 grams and the standard deviation (σ)=8.8 grams
1) The point estimated mean weight of the population is 402.7 grams. This estimate is called the sample mean.
2) c = 99% = 0.99
α = 1 - 0.99 = 0.01
.
The z score of 0.005 corresponds with the z score of 0.495 (0.5 - 0.005).
.
The margin of error (e) = 
The confidence interval = x ± e = 402.7 ± 3.59 = (399.11, 406.29)
3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.
I am 99% sure that the value lies between 399.11 grams and 406.29 grams.
Answer:
d. Internet Protocol
Explanation:
Internet Protocols suite are used to transport packets from the host network across other networks. This task is usually performed by optimizing the size of each available packet, which are then forwarded through the internet protocol (IP) address.
Therefore, Internet Protocol is responsible for packet forwarding.
Since java.util.PriorityQueue doesn't use the Cloneable interface, I think it's safe to say that Serializable interfaces are implemented in all instances.
Answer is power and base
Explanation: both power and base are number variables
Answer:
Umm what? Are you talking about the type of problem it is? If so it is an optimization problem.
Explanation:
I had something like this for one of my tests and I chose the optimization problem because it finds the values of decision variables that result in a maximum or minimum of a function.
But ion know if it's this that you are talking about
