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ioda
3 years ago
15

Jayson started with 200 anger units. Each week he lost 7 anger units. Write an equation that models Jayson's anger after t weeks

.
Mathematics
1 answer:
vovikov84 [41]3 years ago
6 0

Answer:

200 - 7t

Step-by-step explanation:

In order to make an equation, you have to figure out what needs to be put into it. Because Jason starts off with 200 anger units, that number will be subtracted by whatever amount he loses or gains per week, which would be 7. Then, in order to model the number of weeks, you would multiply the variable t to 7, so that it represents how many weeks Jason is going to lose 7 anger units. Therefore, our final equation should be:

Anger units = 200 - 7t

Hope this helps :)

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estimate each product. tell whether the estimate is greater than or less than the actual product. $224×12= 372×36= 488×85= 515×4
Jobisdone [24]
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6 0
4 years ago
Simplify:<br> (4p3 + 6p2 – 7) – (8p? – 7 – 3p)
Kipish [7]

Answer:

4p3 + 6p2 - 8p - 7

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "p2"   was replaced by   "p^2".  1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

 (((4 • (p3)) +  (2•3p2)) -  7) -  8p

STEP

2

:

Equation at the end of step

2

:

 ((22p3 +  (2•3p2)) -  7) -  8p

STEP

3

:

Checking for a perfect cube

3.1    4p3+6p2-8p-7  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  4p3+6p2-8p-7

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -8p-7

Group 2:  4p3+6p2

Pull out from each group separately :

Group 1:   (8p+7) • (-1)

Group 2:   (2p+3) • (2p2)

3.3    Find roots (zeroes) of :       F(p) = 4p3+6p2-8p-7

Polynomial Roots Calculator is a set of methods aimed at finding values of  p  for which   F(p)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  p  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  4  and the Trailing Constant is  -7.

The factor(s) are:

of the Leading Coefficient :  1,2 ,4

of the Trailing Constant :  1 ,7

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        3.00    

     -1       2        -0.50        -2.00    

     -1       4        -0.25        -4.69    

     -7       1        -7.00       -1029.00    

     -7       2        -3.50        -77.00    

     -7       4        -1.75        3.94    

     1       1        1.00        -5.00    

     1       2        0.50        -9.00    

     1       4        0.25        -8.56    

     7       1        7.00        1603.00    

     7       2        3.50        210.00    

     7       4        1.75        18.81    

Final result :

 4p3 + 6p2 - 8p - 7

5 0
3 years ago
How many different license plates are possible if a license plate consists of 2 capital letters followed by 5 digits?
Alina [70]

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The second digit can be any one of 10 digits.  For each one . . .
The third digit can be any one of 10 digits.  For each one . . .
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The total number of possibilities is

                   (26 x 26 x 10 x 10 x 10 x 10 x 10) =

                   ( 26² x 10⁵) = (676 x 100,000) = <em>67,600,000</em> .


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4 years ago
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Answer:

26

Step-by-step explanation:

add 222 and 20

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7 0
3 years ago
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