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Vedmedyk [2.9K]
2 years ago
10

What is the slope-intercept form of the liner equation 2x + 3y = 6?

Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
5 0

Answer:  y = -\frac{2}{3}x+2

Check out the diagram below.

======================================================

Work Shown:

2x + 3y = 6\\\\3y = 6-2x\\\\3y = -2x+6\\\\y = \frac{-2x+6}{3}\\\\y = \frac{-2x}{3}+\frac{6}{3}\\\\y = -\frac{2}{3}x+2\\\\

The steps above show us subtracting 2x from both sides, then we divide both sides by 3 to fully isolate y.

The last equation is in y = mx+b form with m = -\frac{2}{3} as the slope and b = 2 as the y intercept.

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1)


\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})~\hspace{10em} slope = m\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=1[x-(-3)] \\\\\\ y-3=1(x+3)\implies y-3=x+3\implies y=x+6


2)


\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-2}{1-(-4)}\implies \cfrac{10}{1+4}\implies \cfrac{10}{5}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=2[x-(-4)]\implies y-2=2(x+4) \\\\\\ y-2=2x+8\implies y=2x+10

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Read 2 more answers
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