This problem deals with a weighted average. Since the AP classes count twice as much as regular classes, their grades must be counted twice. It's as if for each AP class he's taking, he was taking two classes. The points of each AP class grade is added twice, and the each AP class counts as 2 classes in the number of classes.
Each AP class counts twice and counts as 2 classes.
Class Ben's grade Points Number of Classes
AP English B 3 + 3 2
AP Government B 3 + 3 2
AP Algebra II A 4 + 4 2
Spanish B 3 1
Physics D 1 1
TOTALS 24 8
GPA = (total points)/(number of classes) = 24/8 = 3
<span>Answer: B 3.0</span>
Answer:
x is 4.
Step-by-step explanation:
8 times 8 is 64
64 minus 4 is 60
60 divided by 15 is 4
The bases are both 2, so we would subtract the exponents. This is because the rule is
(a^b)/(a^c) = a^(b-c)
In this case,
a = 2
b = 3/4
c = 1/2
So this means
b - c = (3/4) - (1/2) = (3/4) - (2/4) = 1/4
After subtracting the exponents, the final exponent is 1/4
So the expression simplifies to 2^(1/4) which is the same as
![\sqrt[4]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D)
(fourth root of 2)
The answer is 4+5+6=15.Hope that helps. :)