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harkovskaia [24]
3 years ago
14

Please help me!I will give you 44 points

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

a) 5/4

b) y = 5/4x + 27

Step-by-step explanation:

To find the gradient of a line, simply change the equation into slope intercept form (y = mx + b), where b is the y-intercept and m is the slope.

4y - 5x = 2

4y = 5x + 2

y = 5/4x + 1/2

m(gradient) = 5/4

For lines to be parallel, simply keep the gradient the same.  Any line with a gradient, or slope, of 5/4 will be parallel. As such, simply keep the first two terms identical, and change the y-intercept into any number.

Hope it helps :)

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2 years ago
10. 10. If AB bisects CAF, and m&lt;EAF = 72°,<br>then the m&lt;BAF =​
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The measure of ∠BAF is 54°.

Solution:

DF and CE are intersecting lines.

m∠EAF = 72° and AB bisects ∠CAF.

∠EAF and ∠DAC are vertically opposite angles.

Vertical angle theorem:

<em>If two lines are intersecting, then vertically opposite angles are congruent.</em>

∠DAC ≅ ∠EAF

m∠DAC = 72°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠DAE + m∠EAF = 180°

m∠DAE + 72° = 180°

Subtract 72° from both sides.

m∠DAE = 108°

∠CAF and ∠DAE are vertically opposite angles.

⇒ m∠CAF = m∠DAE

⇒ m∠CAF = 108°

AB bisects ∠CAF means ∠CAB = ∠BAF

m∠CAB + m∠BAF = 108°

m∠BAF + m∠BAF = 108°

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Divide by 2 on both sides, we get

m∠BAF = 54°

Hence the measure of ∠BAF is 54°.

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3 years ago
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