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3 years ago

Estimate the value of two questions : A) 98.5 x 13 B)102.3/4.7

Mathematics

2 answers:

storchak [24]3 years ago

6 0

A. 1279
B.20 (I looked up the answer then went at least one down to show that I estimated)

SVETLANKA909090 [29]3 years ago

4 0

A) 125
b) 25
is my estimation

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3 years ago

A researcher conducted an experiment to investigate the effectiveness of a medicated lotion in treating a skin irritation. A gro

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It can be concluded that the medicated lotion has an effect on treating skin irritations.

Step-by-step explanation:

In this case we need to determine whether the medicated lotion was effective in treating the skin irritation or not.

The hypothesis can be defined as follows:

H₀: There is no difference between the two proportions, i.e. p₁ - p₂ = 0.

Hₐ: There is a significant difference between the two proportions, i.e. p₁ - p₂ ≠ 0.

The information provided is:

n₁ = 40

n₂ = 40

X₁ = 36

X₂ = 16

Compute the sample proportions and total proportions as follows:

$\hat p_{1}=\frac{36}{40}=0.90\\\\\hat p_{2}=\frac{16}{40}=0.40\\\\\hat P=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{36+16}{40+40}=0.65$

Compute the test statistic value as follows:

$z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat P(1-\hat P)[\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}=\frac{0.90-0.40}{\sqrt{0.65(1-0.65)[\frac{1}{40}+\frac{1}{40}]}}=4.69$

The test statistic value is 4.69.

The decision rule is:

The null hypothesis will be rejected if the p-value of the test is less than the significance level.

Compute the p-value as follows:

$p-value=2\times P(Z$

The p-value of the test is very small.

The null hypothesis will be rejected at any significance level.

Thus, there is a significant difference between the two proportions.

So, it can be concluded that the medicated lotion has an effect on treating skin irritations.

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3 years ago